11

安装 FOSUserBundle 后,现在我尝试使用用户/用户密码登录,但仍然收到“错误凭据”消息。这是我的security.yml:

security:
    encoders:
        Symfony\Component\Security\Core\User\User: plaintext

    role_hierarchy:
        ROLE_ADMIN:       ROLE_USER
        ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]

    providers:
        in_memory:
            users:
                user:  { password: userpass, roles: [ 'ROLE_USER' ] }
                admin: { password: adminpass, roles: [ 'ROLE_ADMIN' ] }
        fos_userbundle:
            id: fos_user.user_manager

    firewalls:
        main:
            pattern: ^/
            form_login:
                provider: fos_userbundle
            logout:       true
            anonymous:    true
            #anonymous: ~
            #http_basic:
            #    realm: "Secured Demo Area"

任何的想法?

symfony 2.0.4

4

4 回答 4

22

像这样链接您的提供商:

providers:
    chain_provider:
        providers: [in_memory, fos_userbundle]
    in_memory:
        users:
            user:  { password: userpass, roles: [ 'ROLE_USER' ] }
            admin: { password: adminpass, roles: [ 'ROLE_ADMIN' ] }

    fos_userbundle:
        id: fos_user.user_manager

    firewalls:
        main:
            pattern: ^/
            form_login:
                provider: chain_provider
            logout:       true
            anonymous:    true
            switch_user:  true
        dev:
            pattern:  ^/(_(profiler|wdt)|css|images|js)/
            security: false
于 2011-10-30T01:53:44.220 回答
5

在防火墙部分,您使用了错误的提供程序:fos_userbundle 而不是 in_memory。如果需要,您可以将它们链接起来

于 2011-10-27T14:48:37.367 回答
2

除了用户提供商之外,我建议您在 Web 应用程序中对密码进行编码,您可以通过工具在线sh1 链接进行在线编码

encoders:
    "Symfony\Component\Security\Core\User\User":
        algorithm:   sha1
        iterations: 1
        encode_as_base64: false
    "FOS\UserBundle\Model\UserInterface": sha512

providers:
chain_provider:
    providers: [in_memory, fos_userbundle]
in_memory:
    users:
        user:  { password: 45f106ef4d5161e7aa38cf6c666607f25748b6ca, roles: [ 'ROLE_USER' ] } # userpass as password
        admin: { password: 74913f5cd5f61ec0bcfdb775414c2fb3d161b620, roles: [ 'ROLE_ADMIN' ] } # adminpass as password

fos_userbundle:
    id: fos_user.user_manager

firewalls:
    main:
        pattern: ^/
        form_login:
            provider: chain_provider
        logout:       true
        anonymous:    true
        switch_user:  true
    dev:
        pattern:  ^/(_(profiler|wdt)|css|images|js)/
        security: false
于 2012-02-04T15:38:15.767 回答
0

像这样为 symfony 2.3 链接你的提供者:

providers:

    in_memory:
        users:
            user:  { password: userpass, roles: [ 'ROLE_USER' ] }
            admin: { password: adminpass, roles: [ 'ROLE_ADMIN' ] }

    fos_userbundle:
        id: fos_user.user_manager

    chain_provider:
        chain:
            providers: [in_memory, fos_userbundle]

    firewalls:
        main:
            pattern: ^/
            form_login:
                provider: chain_provider
            logout:       true
            anonymous:    true
            switch_user:  true
        dev:
            pattern:  ^/(_(profiler|wdt)|css|images|js)/
            security: false
于 2013-10-23T19:20:43.513 回答