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鉴于 SQL...

declare @xmlDoc xml
set @xmlDoc = '<people>
  <person PersonID="8" LastName="asdf" />
  <person PersonID="26" LastName="rtert" />
  <person PersonID="33" LastName="dfgh" />
  <person PersonID="514" LastName="ukyy" />
</people>'

将该 xml 转换为包含两列 PersonID 和 LastName 的表的 sql 是什么?

4

2 回答 2

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SELECT T.c.query('.').value('(//@PersonID)[1]', 'int'),
    T.c.query('.').value('(//@LastName)[1]', 'varchar(50)')
FROM @xmlDoc.nodes('/people/person') T(c)
于 2011-10-27T03:06:56.657 回答
2
select T.X.value('@PersonID', 'int') as PersonID,
       T.X.value('@LastName', 'nvarchar(50)') as LastName
from @xmlDoc.nodes('/people/person') as T(X)
于 2011-10-27T05:45:22.183 回答