6

我有以下 appDomainManager 代码

public class HostAppDomainManager : AppDomainManager
{
    public override void InitializeNewDomain(AppDomainSetup appDomainInfo)
    {
        this.InitializationFlags = AppDomainManagerInitializationOptions.RegisterWithHost;
    }
}

并遵循用于启动运行时主机的非托管代码

int _tmain(int argc, _TCHAR* argv[]) 
{ 
    ICLRMetaHost *pMetaHost       = NULL; 
    HRESULT hr;  
    ICLRRuntimeInfo *runtimeInfo = NULL;     
    __try 
    { 
        hr = CLRCreateInstance(CLSID_CLRMetaHost, IID_ICLRMetaHost, (LPVOID*)&pMetaHost); 
        hr = pMetaHost->GetRuntime(L"v4.0.30319",IID_ICLRRuntimeInfo,(LPVOID*)&runtimeInfo); 
        ICLRRuntimeHost *runtimeHost  = NULL; 
        hr = runtimeInfo->GetInterface(CLSID_CLRRuntimeHost,IID_ICLRRuntimeHost, (LPVOID*)&runtimeHost);     
        ICLRControl* clrControl = NULL; 
        hr = runtimeHost->GetCLRControl(&clrControl); 
        hr = clrControl->SetAppDomainManagerType(L"ExceptionThrower.dll",L"ExceptionThrower.HostAppDomainManager");
        hr = runtimeHost->Start();  
    } 
    __except(1) 
    { 
        wprintf(L"\n Error thrown %d",e); 
    } 
    return 0; 
}

对 runtimeHost->Start() 的调用失败，错误代码为 -2146233054，有人可以指出我应该怎么做才能解决这个问题？

4

1 回答 1

6

如果其他人遇到这种情况，问题是实现 AppDomainManager 的 dll 应该被强命名。

所以将代码更改为

hr = clrControl->SetAppDomainManagerType(L"ExceptionThrower, Version=1.0.0.0, Culture=neutral, PublicKeyToken=d3b6b01f2067f563",L"ExceptionThrower.HostAppDomainManager");
于 2011-10-28T16:08:39.657 回答