以下代码:
[TestMethod]
public void CanSerializePerson()
{
var towel1 = new Towel() { Id = 1 };
var towel2 = new Towel() { Id = 2 };
var towel3 = new Towel() { Id = 3 };
var gym = new Gym();
gym.towels.Add(towel1);
gym.towels.Add(towel2);
gym.towels.Add(towel3);
var person = new Person()
{
recentlyUsedTowel = towel1,
gym = gym
};
var sb = new StringBuilder();
using (var writer = XmlWriter.Create(sb))
{
var ser = new DataContractSerializer(typeof (Person));
ser.WriteObject(writer, person);
}
throw new Exception(sb.ToString());
}
public class Person
{
public Towel recentlyUsedTowel { get; set; }
public Gym gym { get; set; }
}
public class Gym
{
public Gym()
{
towels = new List<Towel>();
}
public List<Towel> towels { get; set; }
}
public class Towel
{
public int Id { get; set; }
}
将评估为:
<?xml version="1.0" encoding="utf-16"?>
<Person xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://tempuri.org">
<gym>
<towels>
<Towel><Id>1</Id></Towel>
<Towel><Id>2</Id></Towel>
<Towel><Id>3</Id></Towel>
</towels>
</gym>
<recentlyUsedTowel><Id>1</Id></recentlyUsedTowel>
</Person>
如果您将 IsReference 属性添加到 Towel 类的 DataContract 属性,如下所示:
[DataContract(IsReference=true)]
public class Towel
{
// you have to specify a [DataMember] in this because you are
// explicitly adding DataContract
[DataMember]
public int Id { get; set; }
}
你会得到这样的输出:
<?xml version="1.0" encoding="utf-16"?>
<Person xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://tempuri.org">
<gym>
<towels>
<Towel z:Id="i1" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/">
<Id>1</Id>
</Towel>
<Towel z:Id="i2" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/">
<Id>2</Id>
</Towel>
<Towel z:Id="i3" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/">
<Id>3</Id>
</Towel>
</towels>
</gym>
<recentlyUsedTowel z:Ref="i1" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/" />
</Person>
希望这可以帮助。