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我正在尝试使用 Perl 和Date::Day将给定日期转换为一周中的相应日期。

输入字符串的格式为:October 24, 2011; March 12, 1989; November 26, 1940.

我编写了一个脚本,它将解析上述输入并将每个日期转换为Date::Day::day().

此子例程接受格式为 的输入mm,dd,yyyy。我已经使用哈希完成了这项工作。最近在stackoverflow上发布了一个关于这个查询的线程,并在其他成员的帮助下,能够做到这一点。

这是我的脚本,它为每个日期返回 ERR,而不是返回与日期对应的星期几。

传递给 day() 子例程的参数的输入格式似乎有问题。

这里有更多关于我正在使用的 Perl 模块的文档:http: //helpspy.com/cm/programming/lang/perl/cpan/c06/Date/Day/d_1/

我很想知道,我到底哪里出错了。在将日期作为参数传递给 day() 子例程之前,我是否必须对日期进行一些修改?

#!/usr/bin/perl

use Date::Day;
use strict;
use warnings;

my @arr;

print "Enter the string: ";
my $str=<>;
chomp $str;

my @dates= split /; /,$str;

my %days= ("January",1,"February",2,"March",3,"April",4,"May",5,"June",6,"July",7,"August",8,"September",9,"October",10,"November",11,"December",12);

my @output = map {
my $pattern=$_;
$pattern =~ s/(\S*)\s/$days{$1}, /;
$pattern =~ s/\s//g;
$pattern
} @dates;

print &day(11,9,1987); # for test purpose and it returns correct value

foreach $output (@output)
{
chomp $output;
my $result=&day($output);
push(@arr,$result);
}

foreach my $arr (@arr)
{
print $arr."; ";
}

上述脚本的输出为:ERR;呃; 呃;

4

2 回答 2

5

Date::Day看起来像一个相当古老的模块。它最后一次更新几乎是九年前。这并不是说它坏了,但是这些天DateTime模块系列几乎可以处理您想要的任何日期/时间处理。我强烈建议你看看那些。

这是一个使用 DateTime::Format::Strptime 解决问题的示例。

#!/usr/bin/perl

use strict;
use warnings;
use 5.010;

use DateTime::Format::Strptime;

my $dt_parser = DateTime::Format::Strptime->new(
  pattern => '%B %d, %Y'
);

while (<DATA>) {
  chomp;

  my $dt = $dt_parser->parse_datetime($_);

  say $dt->day_name;
}

__END__
October 24, 2011
March 12, 1989
November 26, 1940
于 2011-10-25T12:25:14.347 回答
3

您正在将一个字符串传递给 sub &day

这是一个重写:

#!/usr/local/bin/perl 
use Data::Dump qw(dump);
use strict;
use warnings;
use Date::Day;

print "Enter the string: ";
my $str=<>;
chomp $str;

my @dates= split /; /,$str;

my %days = ("January",1,"February",2,"March",3,"April",4,"May",5,"June",6,"July",7,"August",8,"September",9,"October",10,"November",11,"December",12);

my @output = map {
    my @l = split/[ ,]+/;
    $l[0] = $days{$l[0]};
    [@l];
} @dates;

my @arr;
foreach my $date(@output) {
    push @arr, &day(@$date);
}
dump@arr;

输出:

("MON", "SUN", "TUE")
于 2011-10-25T09:00:23.410 回答