我正在开发一个黑莓应用程序。当用户按下一个按钮并按住它 2 秒钟时,我想从主屏幕打开一个屏幕。
反正?
谢谢。
这是您问题的代码。我已经使用了这个BlackBerry LongClickListener 实现链接,其中也包含很好的解释。
public class HoldButtonScreen extends MainScreen implements FieldChangeListener {
ButtonField _btnHold;
Timer _timer;
public HoldButtonScreen() {
_btnHold = new ButtonField("Hold 2 sec to get popup")
{
protected boolean navigationClick(int status, int time) {
final Field _btnHold= this;
_timer = new Timer();
System.out.println("hi there");
UiApplication.getUiApplication().invokeLater(new Runnable() {
public void run() {
try{
_timer.schedule(new TimerTask() {
public void run() {
fieldChanged(_btnHold, 0);
}}, 2000);
}catch(Exception e){
e.printStackTrace();
}
}
});
return true;
}
protected boolean navigationUnclick(int status, int time) {
System.out.println("hi unclick");
add(new LabelField("You have't hold button for 2 second."));
_timer.cancel();
return true;
}
};
_btnHold.setChangeListener(this);
add(_btnHold);
}
public void fieldChanged(Field field, int context) {
UiApplication.getUiApplication().invokeLater(new Runnable() {
public void run() {
PopupScreen _popUpScreen = new PopupScreen(new VerticalFieldManager()){
public boolean onClose() {
close();
return true;
}
};
_popUpScreen.add(new LabelField("Hello , i am pop up after 2 second."));
UiApplication.getUiApplication().pushScreen(_popUpScreen);
}
});
}
}
试试这个,这将成功运行。只需更改 PushScreen 中的屏幕。
private Thread splashTread;
protected int _splashTime = 200;
boolean countinue = true;
splashTread = new Thread() {
public void run() {
while (countinue == true) {
try {
synchronized (this) {
wait(_splashTime);
}
} catch (InterruptedException e) {
} finally {
synchronized (UiApplication.getUiApplication().getAppEventLock()) {
UiApplication.getUiApplication().pushScreen(new Login());
SplashScreen.this.close();
}
countinue = false;
}
}
}
};
splashTread.start();