5

我有一个非常不寻常的情况，我希望有人能够对此有所了解。我对 oracle 同义词的理解是，它基本上是另一个模式中表的别名。

当我从同义词中计数时，它返回零行。当我从基础表中执行相同操作时，它会返回 12000 行。

我无法解释这种差异。任何人都可以帮忙吗？

select * from dba_synonyms
where synonym_name = 'CS_INCIDENTS_B_SEC';

OWNER  SYNONYM_NAME        TABLE_OWNER  TABLE_NAME          DB_LINK
------ ------------------- ------------ ------------------- -------
APPS   CS_INCIDENTS_B_SEC  CS           CS_INCIDENTS_ALL_B         



select count(*) from CS.CS_INCIDENTS_ALL_B;

COUNT(*)               
---------------------- 
12549                  

select count(*) from APPS.CS_INCIDENTS_B_SEC;

COUNT(*)               
---------------------- 
0

解释计划：

直接上桌...

EXPLAIN PLAN FOR
SELECT  *
FROM    CS.CS_INCIDENTS_ALL_B

PLAN_TABLE_OUTPUT
--------------------------------------------------------------------------
| Id  | Operation         | Name               | Rows | Bytes| Cost(%CPU)|
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |                    | 6056 | 1549K|  122   (3)|
|   1 |  TABLE ACCESS FULL| CS_INCIDENTS_ALL_B | 6056 | 1549K|  122   (3)|
--------------------------------------------------------------------------

通过同义词...

EXPLAIN PLAN FOR
SELECT  *
FROM    APPS.CS_INCIDENTS_B_SEC

PLAN_TABLE_OUTPUT
---------------------------------------------------------------------------
| Id  | Operation          | Name               | Rows | Bytes| Cost(%CPU)|
---------------------------------------------------------------------------
|   0 | SELECT STATEMENT   |                    |    1 |  262 |    0   (0)|
|*  1 |  FILTER            |                    |      |      |           |
|   2 |   TABLE ACCESS FULL| CS_INCIDENTS_ALL_B | 6056 | 1549K|  122   (3)|
---------------------------------------------------------------------------

1 - filter(NULL IS NOT NULL)

同义词链...

SQL> SELECT  *
  2  FROM    dba_synonyms
  3  START WITH
  4          owner = 'CS'
  5          AND synonym_name = 'CS_INCIDENTS_ALL_B'
  6  CONNECT BY
  7          owner = PRIOR table_owner
  8          AND synonym_name = PRIOR table_name
  9  /

no rows selected

SQL> SELECT  *
  2  FROM    dba_synonyms
  3  START WITH
  4          owner = 'APPS'
  5          AND synonym_name = 'CS_INCIDENTS_B_SEC'
  6  CONNECT BY
  7          owner = PRIOR table_owner
  8          AND synonym_name = PRIOR table_name
  9  /

正在检查数据库上的策略...

SQL> SELECT *
  2  FROM dba_policies
  3  WHERE OBJECT_NAME = 'CS_INCIDENTS_B_SEC'
  4  /

OBJECT_OWNER  OBJECT_NAME         POLICY_GROUP  POLICY_NAME          
------------- ------------------- ------------- -------------------- 
APPS          CS_INCIDENTS_B_SEC  SYS_DEFAULT   CS_SR_SEC_SR_ACCESS  


PF_OWNER  PACKAGE            FUNCTION       SEL INS UPD DEL IDX CHK 
--------- ------------------ -------------- --- --- --- --- --- --- 
APPS      FND_GENERIC_POLICY GET_PREDICATE  YES NO  NO  NO  NO  NO  


ENABLE STATIC_POLICY POLICY_TYPE  LONG_PREDICATE
------ ------------- ------------ --------------
YES    NO            DYNAMIC      YES
4

3 回答 3

5

更新：

您已ROW LEVEL SECURITY启用。

FND_GENERIC_POLICY.GET_PREDICATE每次访问表时都会调用user 函数并限制对某些行的访问。

它会根据您如何访问表返回不同的结果：直接或通过SYNONYM.

您需要查看函数并查看发生了什么（或在此处发布函数文本）。

于 2009-04-23T11:11:32.510 回答
0

您是否 100% 确定这CS.CS_INCIDENTS_ALL_B实际上是一个表格而不是一个视图？如果它是一个视图，也许它在 WHERE 子句中做了一些不寻常的事情。

select object_type from dba_objects where owner = 'CS' and object_name = 'CS_INCIDENTS_ALL_B'
于 2009-04-23T11:10:33.840 回答
0

检查以确保没有其他与您的同义词同名的 APPS 拥有的对象（视图或表）。

select object_type,object_name
from   dba_objects
where  object_name='CS_INCIDENTS_B_SEC'
and    owner='APPS'
and    object_type!='SYNONYM'
于 2009-04-23T12:40:28.833 回答