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我正在尝试使用 AlchemyAPI Python 0.7 SDK。但是，当我在其中运行一个方法时，例如 URLGetText(url);

我收到此错误：

    nodes = etree.fromstring(result).xpath(xpathQuery)
  File "lxml.etree.pyx", line 2743, in lxml.etree.fromstring (src/lxml/lxml.etree.c:52665)
  File "parser.pxi", line 1573, in lxml.etree._parseMemoryDocument (src/lxml/lxml.etree.c:79932)
  File "parser.pxi", line 1452, in lxml.etree._parseDoc (src/lxml/lxml.etree.c:78774)
  File "parser.pxi", line 960, in lxml.etree._BaseParser._parseDoc (src/lxml/lxml.etree.c:75389)
  File "parser.pxi", line 564, in lxml.etree._ParserContext._handleParseResultDoc (src/lxml/lxml.etree.c:71739)
  File "parser.pxi", line 645, in lxml.etree._handleParseResult (src/lxml/lxml.etree.c:72614)
  File "parser.pxi", line 585, in lxml.etree._raiseParseError (src/lxml/lxml.etree.c:71955)
lxml.etree.XMLSyntaxError: AttValue: " or ' expected, line 19, column 11

这来自这个代码区域：

  def GetRequest(self, apiCall, apiPrefix, paramObject):
    endpoint = 'http://' + self._hostPrefix + '.alchemyapi.com/calls/' + apiPrefix + '/' + apiCall
    endpoint += '?apikey=' + self._apiKey + paramObject.getParameterString()
    handle = urllib.urlopen(endpoint)
    result = handle.read()
    handle.close()
    xpathQuery = '/results/status'
    nodes = etree.fromstring(result).xpath(xpathQuery)
    if nodes[0].text != "OK":
      raise Exception, 'Error making API call.'
    return result

有人对出了什么问题有任何想法吗？

谢谢你

丹尼尔·克肖

4

1 回答 1

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我查看了 Python urllib 文档，发现了这个页面：

http://docs.python.org/library/urllib.html#high-level-interface

filehandle其中包含有关由以下对象返回的对象的警告urllib.urlopen()：

一个警告：read() 方法，如果 size 参数被省略或为负，可能直到数据流结束才读取；在一般情况下，没有很好的方法来确定来自套接字的整个流是否已被读取。

我认为也许您应该确保在使用etree.fromstring()API 解析文件之前将文件的全部内容作为 Python 字符串获取。就像是：

result = ''
while (1):
    next = handle.read()
    if not next: 
        break
    result += next
于 2011-10-15T16:22:03.960 回答