45

我想让我的图表看起来像这样：

但我只能得到这个：

问题是，rankdir 在subgraph. 那么，如何模仿呢？

编码：

digraph G {
    node [shape = circle]
    0 [style = invis]

    0 -> "0A"

    subgraph clusterA {
        label=A
        "0A"
        "1A"
        "2A" -> "0A" [label=•]
    }

    subgraph clusterB {
        label=B
        "0B"
        "1B"
        "2B" -> "0B" [label=•]
    }

        subgraph clusterC {
        label=C
        "0C"
        "1C"
        "2C" -> "0C" [label=•]
    }

    subgraph clusterD {
        label=D
        "0D"
        "1D"
        "2D" -> "0D" [label=•]
    }

    subgraph clusterE {
        label=E
        "0E"
        "1E"
        "2E" -> "0E" [label=•]
    }

    subgraph clusterF {
        label=F
            {node [shape = doublecircle] "0F" "1F"}
        "2F" -> "0F" [label=•]
    }

    "0A" -> "1B" [label=a]
    "1A" -> "2B" [label=a]
    "0B" -> "1C" [label=b]
    "1B" -> "2C" [label=b]
    "0C" -> "1D" [label=c]
    "1C" -> "2D" [label=c]
    "0D" -> "1E" [label=d]
    "1D" -> "2E" [label=d]
    "0E" -> "1F" [label=e]
    "1E" -> "2F" [label=e]
}
4

5 回答 5

57

重现特定的图形布局通常可以通过以下方式实现：

  • 不可见的节点和边
  • 排名约束

这是我复制您的图表的方式 - 或至少是其中的一部分：

digraph g {
    rankdir="LR";
    node[shape = circle, fontsize=14];
    fontsize=18;
    labeljust="l";

    edge[style=invis, fontsize=12];

    { rank=same;
        0 [style = invis];
        01 [style = invis];
        02 [style=invis];
        0 -> 01 -> 02;
    }

    subgraph clusterA {
        "0A" -> "1A" -> "2A";
        "2A" -> "0A" [label=".", constraint=false, style=solid];
        label="A";
    }

    subgraph clusterB {
        "0B" -> "1B" -> "2B";
        "2B" -> "0B" [label=".", constraint=false, style=solid];
        label="B";
    }

    subgraph clusterC {
        "0C" -> "1C" -> "2C";
        "2C" -> "0C" [label=".", constraint=false, style=solid];
        label="C";
    }

    0 -> "0A"[style=solid];
    01 -> "0B"[style=invis];
    02 -> "0C"[style=invis];

    // edges between clusters
    edge[constraint=false, style=solid];
    "0A" -> "1B" [label=a]
    "1A" -> "2B" [label=a]
    "0B" -> "1C" [label=b]
    "1B" -> "2C" [label=b]
}

这个解决方案不是很直观。实现这一点的几点：

  • 我选择了rankdir="LR"比 更好的边缘TB，尽管它与图形的方向并不真正对应
  • 不可见节点和边用于顶级节点（0、01、02），以使集群左对齐。
  • （不可见的）顶部节点被强制为相同的等级并由不可见的边链接 - 这将确保链接到每个节点的集群以正确的顺序出现。

结果是：

图形输出

于 2011-10-16T21:34:26.927 回答
2

使用 constraint=false 应该让你的子图中的节点变成你想要的方式 http://www.graphviz.org/doc/info/attrs.html#d:constraint

subgraph clusterB {
    label=B
    "0B"
    "1B"
    "2B" -> "0B" [constraint=false label=•]
}

之后你会发现你的子图并没有按照你想要的方式排列。像这样的东西可以解决这个问题。

"0A" -> "0B" -> "0C" -> "0D" -> "0E" [weight=999 style=invis];
于 2011-10-16T16:24:26.163 回答
1

rankdir 不能直接在子图中工作，但如果你添加另一组花括号 - 无论叫什么 - rankdir 都有效。见下文。然后，显然您需要更多技巧来恢复您所追求的对齐和排序。

digraph G {
    node [shape = circle]
    0 [style = invis]

    0 -> "0A"

    subgraph clusterA {
        label=A
        {
            rank=same
            "0A"
            "1A"
            "2A" -> "0A" [label=•]
        }
    }

    subgraph clusterB {
        label=B
        {
            rank=same
            "0B"
            "1B"
            "2B" -> "0B" [label=•]
        }
    }

    subgraph clusterC {
        label=C
        {
            rank=same
            "0C"
            "1C"
            "2C" -> "0C" [label=•]
        }
    }

    subgraph clusterD {
        label=D
        {
            rank=same
            "0D"
            "1D"
            "2D" -> "0D" [label=•]
        }
    }

    subgraph clusterE {
        label=E
        {
            rank=same
            "0E"
            "1E"
            "2E" -> "0E" [label=•]
        }
    }

    subgraph clusterF {
        label=F
        {
            rank=same
            {node [shape = doublecircle] "0F" "1F"}
            "2F" -> "0F" [label=•]
        }
    }

    "0A" -> "1B" [label=a]
    "1A" -> "2B" [label=a]
    "0B" -> "1C" [label=b]
    "1B" -> "2C" [label=b]
    "0C" -> "1D" [label=c]
    "1C" -> "2D" [label=c]
    "0D" -> "1E" [label=d]
    "1D" -> "2E" [label=d]
    "0E" -> "1F" [label=e]
    "1E" -> "2F" [label=e]
}

在此处输入图像描述

于 2019-04-26T17:40:37.410 回答
0

使用@marapet 的答案更新group 

digraph g {
rankdir="LR";
node[shape = circle, fontsize=14];
fontsize=18;
labeljust="l";

edge[style=invis, fontsize=12];

{ rank=same;
    0 [group=a style = invis];
    01 [style = invis];
    02 [group=b style=invis];
    0 -> 01 -> 02;
}

subgraph clusterA {
    "0A" [group=a]
    "0A" -> "1A" -> "2A";
    "2A" -> "0A" [label=".", constraint=false, style=solid];
    label="A";
}

subgraph clusterB {
    "0B" -> "1B" -> "2B";
    "2B" -> "0B" [label=".", constraint=false, style=solid];
    label="B";
}

subgraph clusterC {
    "0C" [group=b]
    "1C" [group=b]
    "0C" -> "1C" -> "2C";
    "2C" -> "0C" [label=".", constraint=false, style=solid];
    label="C";
}

0 -> "0A"[style=solid];
01 -> "0B"[style=invis];
02 -> "0C"[style=invis];

// edges between clusters
edge[constraint=false, style=solid];
"0A" -> "1B" [label=a]
"1A" -> "2B" [label=a]
"0B" -> "1C" [label=b]
"1B" -> "2C" [label=b]
}
于 2018-12-06T12:09:31.283 回答
0

看起来 rank=same 可能是一个更清洁的解决方案。看看在 Graphviz 中将集群放在同一等级上。

于 2021-06-28T02:29:40.060 回答