我有一张桌子1
tid letter1 letter2
1 a e
2 p b
3 c k
4 pp bb
5 rr ll
和另一个表2
t2id word
1 banana
2 strawberry
3 apple
4 grape
在 table1 上的替换过程之后,我需要一个 mysql 函数来将输入单词与 table2 中的单词进行比较,例如:
SELECT CHAR_LENGTH(word) AS charl FROM table2;
DECLARE i INT DEFAULT 0;
SET query = CONCAT(
' SELECT word FROM table2 WHERE ( ',
WHILE i < charl DO
//if word's i'nth letter found in the table1
IF (SELECT letter2 FROM table1 WHERE word{i} = letter1)
//replace letter1 with letter2 on this row
'REPLACE(word,letter1,letter2) AND ',
END;
' ) = 'inputword' ';
我的mysql知识太差了。我怎样才能做到这一点?