ruby - 正则表达式在里面获取文本

Question

我一直试图在句子中获取第一个位置名称。所需的位置名称将准确地从第一句的第二个大写字母开始，然后准确地在第一个点之前结束（。）

例子：

 It is located at Supreme Court. Follow by some other text. 
                  ^           ^

期望输出

最高法院

抱歉，我无法向您展示我目前掌握的一段代码。经过一个小时的尝试，我一无所获。

如果您在 Ruby 中显示代码示例，将不胜感激。

Answer 1

这个正则表达式：

regexp = /^.*?[A-Z].*?([A-Z].*?)\./
match = regexp.match(subject)
if match
    match = match[1]
else
    match = ""
end

将产生：Supreme Court

我从匹配第一个大写字母的字符串的开头开始，而忽略其他所有内容。然后我匹配第二个大写并将结果保存到反向引用 1 直到第一个点。

Answer 2

这对我有用：

irb(main):001:0> location = "It is located at Supreme Court. Follow by some other text."
=> "It is located at Supreme Court. Follow by some other text."
irb(main):002:0> location.match(/[^A-Za-z][\bA-Z][\w\s]*\./)
=> #<MatchData "Supreme Court.">

Answer 3

s = 'It is located at Supreme Court. Follow by some other text.'
m = s.match /[A-Z][^A-Z]+([A-Z][^\.]+)/
result = m[1] #Supreme Court

Answer 4

试试这个：

s = 'It is located at Supreme Court. Follow by some other text.'
/[A-Z].+?([A-Z].*)\..+?/.match(s)[1]

Answer 5

这假设字符串的开头没有空格，因此它会查找紧跟在空格之后的第一个大写字母并抓取任何内容，直到找到的第一个句点。

str = "It is located at Supreme Court. Follow by some other text."
m = str.match(/\s([A-Z].*?)\./)
location = m.nil? ? "" : m[1] #just in case there's no match

p location #=> Supreme Court