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我想通过实现 IXmlSerializable 来创建自定义 xml 序列化。我有这个实现 IXmlSerializable 接口的测试类：

[Serializable]
public class Employee : IXmlSerializable
{
    public Employee()
    {
        Name = "Vyacheslav";

        Age = 23;                 
    }

    public string Name{get; set;}

    public int Age { get; set; }



    public System.Xml.Schema.XmlSchema GetSchema()
    {
        return null;
    }

    public void ReadXml(XmlReader reader)
    {
        this.Name = reader["Name"].ToString();
        this.Age = Int32.Parse(reader["Age"].ToString());
    }

    public void WriteXml(XmlWriter writer)
    {
        XmlWriterSettings settings = new XmlWriterSettings();
        settings.OmitXmlDeclaration = true;
        settings.ConformanceLevel = ConformanceLevel.Fragment;

        XmlWriter newWriter = XmlWriter.Create(writer, settings);
        newWriter.WriteAttributeString("Name", this.Name);
        newWriter.WriteAttributeString("Age", this.Age.ToString());            
    }
}

我想要做的是省略 xml 声明。为此，我创建了适当的 XmlWriterSettings 实例并将其作为第二个参数传递以创建新的 XmlWriter。但是当我调试这段代码时，我看到 newWriter.Settings.OmitXmlDeclaration 设置为 false 并且序列化数据包含标记。我究竟做错了什么？

实际的序列化如下所示：

        var me = new Employee();

        XmlSerializer serializer = new XmlSerializer(typeof(Employee));
        TextWriter writer = new StreamWriter(@"D:\file.txt");
        serializer.Serialize(writer, me);
        writer.Close();

第二个问题是 - 如果我想序列化在要序列化的字段中具有自定义类型 ContactInfo 的 Employee 类型，我是否也需要在 ContactInfo 上实现 IXmlSerializable ？

4

1 回答 1

3

The writer-settings is a function of the outermost writer; you should be applying that to the code that creates the file, i.e.

using(var file = File.Create("file.txt"))
using(var writer = XmlWriter.Create(file, settings))
{
    serializer.Serialize(writer, me);
}

additionally, then, you don't need to implement IXmlSerializable. You cannot do this at the inner level - it is too late.

For example:

using System.IO;
using System.Xml;
using System.Xml.Serialization;
public class Employee 
{
    [XmlAttribute] public string Name { get; set; }
    [XmlAttribute] public int Age { get; set; }
}
class Program
{
    static void Main()
    {
        var settings = new XmlWriterSettings();
        settings.OmitXmlDeclaration = true;
        var me = new Employee {
            Name = "Vyacheslav", Age = 23
        };
        var serializer = new XmlSerializer(typeof (Employee));
        using (var file = File.Create("file.txt"))
        using (var writer = XmlWriter.Create(file, settings))
        {
            serializer.Serialize(writer, me);
        }
    }
}

and if you don't want the extra namespaces, then:

        var ns = new XmlSerializerNamespaces();
        ns.Add("", "");
        serializer.Serialize(writer, me, ns);

which generates the file:

<Employee Name="Vyacheslav" Age="23" />
于 2011-10-11T08:04:19.680 回答