我在 postgres 中使用交叉表函数。基本 SQL 是:
select distinct
o_location,
co_name,
o_date,
o_ndate,
o_day,
o_hour,
o_type
from outputs_txt
left join courses on o_course = co_foreign
left join locations on o_location = l_code
where o_date = '2011-10-10'
order by o_hour
我的交叉表查询是
SELECT *
FROM crosstab(
'SELECT DISTINCT
COALESCE(o_location, '''')
,o_hour AS hour
,c.co_name
FROM outputs_txt AS d
LEFT JOIN courses AS c
on o_course = c.co_foreign
LEFT JOIN locations as a
on o_location = a.l_code
WHERE d.o_date = ''2011-10-10'''
)
AS ct(
o_location varchar
,hour_0 varchar
,hour_1 varchar
,hour_2 varchar
,hour_3 varchar
,hour_4 varchar
,hour_5 varchar
,hour_6 varchar
,hour_7 varchar
,hour_8 varchar
,hour_9 varchar
,hour_10 varchar
,hour_11 varchar
,hour_12 varchar
,hour_13 varchar
,hour_14 varchar
,hour_15 varchar
,hour_16 varchar
,hour_17 varchar)
问题是结果都向左移动了。
例如,如果某个位置的课程应显示在hour_8
其上,则会显示在 中hour_0
。
这适用于所有地点的所有课程。它们都左对齐。
我哪里错了?