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首先,我想说这是我唯一的 java 经验。我已经把 c++ 搞砸了,但它已经有一段时间了,所以这可能只是对 java 类缺乏理解的愚蠢。

好的,所以我有一个名为 Player 的简单类文件:

package com.iRprojects.HelloAgain;


public class Player{
    public int Health;
    public int Strength;
    public String Name;

}

然后我有另一个名为 Options 的类(这是我决定使用的以前的活动。这也是从另一个名为主菜单的活动中打开的。)

package com.iRprojects.HelloAgain;


import android.app.Activity;
import android.view.View;
import android.os.Bundle;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

import com.iRprojects.HelloAgain.Player;



public class Options extends Activity {

        EditText name;
        Button getName;

        TextView playerName;

        Player playerOne;




        @Override

        public void onCreate(Bundle options) {
            super.onCreate(options);



            setContentView(R.layout.options);


            name = (EditText) findViewById(R.id.tName);
            getName = (Button) findViewById(R.id.bGetName);

            playerName = (TextView) findViewById(R.id.vName);

            getName.setOnClickListener(new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    playerOne.Name = name.getText().toString(); //This is the problem

                    playerName.setText(playerOne.Name);
                }
            });


        }


}

我正在尝试使用来自 EditText 的输入来设置播放器名称,但是当我单击“getName”按钮时它会崩溃。我认为可以说我错误地设置了类,错误地创建了类成员,或者调用/声明了错误的变量。任何帮助,将不胜感激。

如果有帮助,这是调试日志:

HelloAgain [Android Application]    
    DalvikVM[localhost:8600]    
        Thread [<1> main] (Suspended (exception NullPointerException))  
            Options$1.onClick(View) line: 46    
            Button(View).performClick() line: 2485  
            View$PerformClick.run() line: 9080  
            ViewRoot(Handler).handleCallback(Message) line: 587 
            ViewRoot(Handler).dispatchMessage(Message) line: 92 
            Looper.loop() line: 123 
            ActivityThread.main(String[]) line: 3683    
            Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method]  
            Method.invoke(Object, Object...) line: 507  
            ZygoteInit$MethodAndArgsCaller.run() line: 864  
            ZygoteInit.main(String[]) line: 622 
            NativeStart.main(String[]) line: not available [native method]  
        Thread [<8> Binder Thread #2] (Running) 
        Thread [<7> Binder Thread #1] (Running) 
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1 回答 1

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您必须创建一个 Player 实例并将其分配给 playerOne 变量。

Player playerOne = new Player();
于 2011-10-10T05:55:16.347 回答