java - 如何提取正确的字符串？

Question

我有一个这样的字符串：

 14.809180,56.876968,0.000000 14.808170,56.877048,0.000000 14.805100,56.877220,0.000000 14.804130,56.877338,0.000000

即，一开始有一个空格，在 0.000000 之后还有一个空格。我只想提取14.XYZ和56.XYZ. 我怎样才能做到这一点？

Answer 1

根据我的评论，尝试 String#split(...)，例如：

  String test = "14.809180,56.876968,0.000000 14.808170,56.877048,0.000000 14.805100,56.877220,0.000000";
  String[] tokens = test.split("[,\\s]+");
  for (String token : tokens) {
     System.out.println(token);
  }

"[,\\s]+"是一个正则表达式，它帮助 split 方法使用一个或多个空格字符 (\s) 或逗号来拆分字符串。

Answer 2

用于String.split()分隔每个数字，然后Double.valueOf()将其转换为double.

String string = "14.809180,56.876968,0.000000 14.808170,56.877048,0.000000 14.805100,56.877220,0.000000 14.804130,56.877338,0.000000";
String[] numStrings = string.split("[ ,]");
for (String num : numStrings) {
    double d = Double.valueOf(num);
    // ...
}

Answer 3

这将拆分并遍历输入字符串中的所有小数

String groups[] = input.split(" ");
for(int i = 0; i < groups.length; i++) {
   String decimals[] = groups[i].split(",");
   for(int j = 0; j < decimals.length; j++) {
      float f = Float.parseFloat(decimals[j]);
      //do something with f
   }
}

Answer 4

这可能不是最漂亮的解决方案，但它会起作用。

String[] myStrings = uglyString.spli(",");
Integer firstNum = new Integer(myStrings[0]);
Integer secondNum = new Integer(myStrings[1]);