python - 如何对 WeekArchiveView 进行分页？

Question

继续我的斗争，我WeekArchiveView如何按周对它进行分页？

我想要的是：

• 知道是否有下周/上周可用；
• 如果有，请在模板中提供链接。

我希望它也能跳过空旷的几周。

源显示get_next_day/get_prev_day和get_next_month/get_prev_month可用，但数周内都没有。

Answer 1

这绝对很有趣。果然是MonthMixinincludes get_next_month/ get_prev_monthmethods，还有DayMixinincludes get_next_day/ get_prev_daymethods。然而， YearMixin 和 WeekMixin 在它们的定义中没有等效的功能。似乎对 Django 团队来说有点疏忽。

我认为您最好的选择是继承 WeekArchiveView 或 BaseWeekArchiveView （如果您最终可能想要更改响应格式并且不想重新实现您的方法）并添加您自己的get_next_week/get_prev_week方法。然后让您的视图从您的子类继承。对 s 方法进行简单的修改DayMixin就足够了。

def get_next_week(self, date):
    """
    Get the next valid week.
    """
    next = date + datetime.timedelta(days=7)
    return _get_next_prev_month(self, next, is_previous=False, use_first_day=False)

def get_previous_week(self, date):
    """
    Get the previous valid week.
    """
    prev = date - datetime.timedelta(days=7)
    return _get_next_prev_month(self, prev, is_previous=True, use_first_day=False)

Answer 2

以chrisdpratt 的代码为基础，我创建了一个类，该类为模板提供next_week和previous_week：

class BetterWeekArchiveView(WeekArchiveView):

    def get_next_week(self, date):
        """
        Get the next valid week.
        """
        next = date + timedelta(days=7)
        return _get_next_prev_month(self, next, is_previous=False, use_first_day=False)

    def get_previous_week(self, date):
        """
        Get the previous valid week.
        """
        prev = date - timedelta(days=7)
        return _get_next_prev_month(self, prev, is_previous=True, use_first_day=False)

    def get_dated_items(self):
        """
        Return (date_list, items, extra_context) for this request.
        Inject next_week and previous_week into extra_context.
        """
        result = super(BetterWeekArchiveView, self).get_dated_items()
        extra_context = result[2]
        date = extra_context['week']

        extra_context.update({
            'next_week': self.get_next_week(date),
            'previous_week': self.get_previous_week(date),
        })

        return result

这很完美。