下面的这个 HMACSHA1 代码用于将“密码”和“消息”转换AFF791FA574D564C83F6456CC198CBD316949DC9
为http://buchananweb.co.uk/security01.aspx的证据。
我的问题是,是否有可能:
BYTE HMAC[] = {0x50,0x61,0x73,0x73,0x77,0x6F,0x72,0x64};
BYTE data2[] = {0x4D,0x65,0x73,0x73,0x61,0x67,0x65};
并且仍然得到相同的值:AFF791FA574D564C83F6456CC198CBD316949DC9
.
例如,如果我在服务器上并收到数据包:
[HEADER] 08 50 61 73 73 77 6F 72 64 00
[HEADER] 07 4D 65 73 73 61 67 65 00
我从数据包中撕下50 61 73 73 77 6F 72 64
&4D 65 73 73 61 67 65
并将其用于我的 HMACSHA1。我将如何去做以获得正确的 HMACSHA1 值?
BYTE HMAC[] = "Password";
BYTE data2[] = "Message";
//BYTE HMAC[] = {0x50,0x61,0x73,0x73,0x77,0x6F,0x72,0x64};
//BYTE data2[] = {0x4D,0x65,0x73,0x73,0x61,0x67,0x65};
HMAC_CTX ctx;
result = (unsigned char*) malloc(sizeof(char) * result_len);
ENGINE_load_builtin_engines();
ENGINE_register_all_complete();
HMAC_CTX_init(&ctx);
HMAC_Init_ex(&ctx, HMAC, strlen((const char*)HMAC), EVP_sha1(), NULL);
HMAC_Update(&ctx, data2, strlen((const char*)(data2)));
HMAC_Final(&ctx, result, &result_len);
HMAC_CTX_cleanup(&ctx);
std::cout << "\n\n";
for(int i=0;i<result_len;i++)
std::cout << setfill('0') << setw(2) << hex << (int)result[i];
int asd;
std::cin >> asd;
// AFF791FA574D564C83F6456CC198CBD316949DC9
编辑:
它通过这样做来工作:
BYTE HMAC[] = {0x50,0x61,0x73,0x73,0x77,0x6F,0x72,0x64, 0x00};
BYTE data2[] = {0x4D,0x65,0x73,0x73,0x61,0x67,0x65, 0x00};
最后加上 0x00。但是,我的问题更多是从数据中提取它并使用它......它仍然可以吗?