有没有人有任何好的 c# 代码(和正则表达式)来解析字符串并“链接”可能在字符串中的任何 url?
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30531 次
7 回答
46
这是一个非常简单的任务,您可以使用Regex和现成的正则表达式来实现它:
就像是:
var html = Regex.Replace(html, @"^(http|https|ftp)\://[a-zA-Z0-9\-\.]+" +
"\.[a-zA-Z]{2,3}(:[a-zA-Z0-9]*)?/?" +
"([a-zA-Z0-9\-\._\?\,\'/\\\+&%\$#\=~])*$",
"<a href=\"$1\">$1</a>");
您可能不仅对创建链接感兴趣,而且对缩短 URL 感兴趣。这是一篇关于这个主题的好文章:
另见:
于 2009-04-16T21:30:09.480 回答
13
好吧,在对此进行了大量研究之后,并多次尝试修复时间
- 人们在同一个帖子中输入http://www.sitename.com和 www.sitename.com
- 修复括号,如 ( http://www.sitename.com ) 和http://msdn.microsoft.com/en-us/library/aa752574(vs.85).aspx
- 长网址,例如:http ://www.amazon.com/gp/product/b000ads62g/ref=s9_simz_gw_s3_p74_t1?pf_rd_m=atvpdkikx0der&pf_rd_s=center-2&pf_rd_r=04eezfszazqzs8xfm9yd&pf_rd_t=101&pf_rd_p=4_i=47038786
我们现在正在使用这个 HtmlHelper 扩展......我想我会分享并获得任何评论:
private static Regex regExHttpLinks = new Regex(@"(?<=\()\b(https?://|www\.)[-A-Za-z0-9+&@#/%?=~_()|!:,.;]*[-A-Za-z0-9+&@#/%=~_()|](?=\))|(?<=(?<wrap>[=~|_#]))\b(https?://|www\.)[-A-Za-z0-9+&@#/%?=~_()|!:,.;]*[-A-Za-z0-9+&@#/%=~_()|](?=\k<wrap>)|\b(https?://|www\.)[-A-Za-z0-9+&@#/%?=~_()|!:,.;]*[-A-Za-z0-9+&@#/%=~_()|]", RegexOptions.Compiled | RegexOptions.IgnoreCase);
public static string Format(this HtmlHelper htmlHelper, string html)
{
if (string.IsNullOrEmpty(html))
{
return html;
}
html = htmlHelper.Encode(html);
html = html.Replace(Environment.NewLine, "<br />");
// replace periods on numeric values that appear to be valid domain names
var periodReplacement = "[[[replace:period]]]";
html = Regex.Replace(html, @"(?<=\d)\.(?=\d)", periodReplacement);
// create links for matches
var linkMatches = regExHttpLinks.Matches(html);
for (int i = 0; i < linkMatches.Count; i++)
{
var temp = linkMatches[i].ToString();
if (!temp.Contains("://"))
{
temp = "http://" + temp;
}
html = html.Replace(linkMatches[i].ToString(), String.Format("<a href=\"{0}\" title=\"{0}\">{1}</a>", temp.Replace(".", periodReplacement).ToLower(), linkMatches[i].ToString().Replace(".", periodReplacement)));
}
// Clear out period replacement
html = html.Replace(periodReplacement, ".");
return html;
}
于 2009-07-10T21:48:40.767 回答
7
protected string Linkify( string SearchText ) {
// this will find links like:
// http://www.mysite.com
// as well as any links with other characters directly in front of it like:
// href="http://www.mysite.com"
// you can then use your own logic to determine which links to linkify
Regex regx = new Regex( @"\b(((\S+)?)(@|mailto\:|(news|(ht|f)tp(s?))\://)\S+)\b", RegexOptions.IgnoreCase );
SearchText = SearchText.Replace( " ", " " );
MatchCollection matches = regx.Matches( SearchText );
foreach ( Match match in matches ) {
if ( match.Value.StartsWith( "http" ) ) { // if it starts with anything else then dont linkify -- may already be linked!
SearchText = SearchText.Replace( match.Value, "<a href='" + match.Value + "'>" + match.Value + "</a>" );
}
}
return SearchText;
}
于 2009-04-16T23:02:56.197 回答
4
这并不像您在Jeff Atwood的这篇博文中所读到的那么容易。检测 URL 的结束位置尤其困难。
例如,是否是 URL 的尾括号部分:
- http://en.wikipedia.org/wiki/PCTools(CentralPointSoftware)
- 括号中的 URL (http://en.wikipedia.org) 更多文本
在第一种情况下,括号是 URL 的一部分。在第二种情况下,他们不是!
于 2009-04-16T21:45:01.283 回答
1
发现以下正则表达式 http://daringfireball.net/2010/07/improved_regex_for_matching_urls
对我来说看起来很好。Jeff Atwood 解决方案不能处理很多情况。在我看来, josefresno似乎可以处理所有案件。但是当我试图理解它时(如果有任何支持请求),我的大脑就沸腾了。
于 2011-10-18T14:19:45.243 回答
1
有类:
public class TextLink
{
#region Properties
public const string BeginPattern = "((http|https)://)?(www.)?";
public const string MiddlePattern = @"([a-z0-9\-]*\.)+[a-z]+(:[0-9]+)?";
public const string EndPattern = @"(/\S*)?";
public static string Pattern { get { return BeginPattern + MiddlePattern + EndPattern; } }
public static string ExactPattern { get { return string.Format("^{0}$", Pattern); } }
public string OriginalInput { get; private set; }
public bool Valid { get; private set; }
private bool _isHttps;
private string _readyLink;
#endregion
#region Constructor
public TextLink(string input)
{
this.OriginalInput = input;
var text = Regex.Replace(input, @"(^\s)|(\s$)", "", RegexOptions.IgnoreCase);
Valid = Regex.IsMatch(text, ExactPattern);
if (Valid)
{
_isHttps = Regex.IsMatch(text, "^https:", RegexOptions.IgnoreCase);
// clear begin:
_readyLink = Regex.Replace(text, BeginPattern, "", RegexOptions.IgnoreCase);
// HTTPS
if (_isHttps)
{
_readyLink = "https://www." + _readyLink;
}
// Default
else
{
_readyLink = "http://www." + _readyLink;
}
}
}
#endregion
#region Methods
public override string ToString()
{
return _readyLink;
}
#endregion
}
在此方法中使用它:
public static string ReplaceUrls(string input)
{
var result = Regex.Replace(input.ToSafeString(), TextLink.Pattern, match =>
{
var textLink = new TextLink(match.Value);
return textLink.Valid ?
string.Format("<a href=\"{0}\" target=\"_blank\">{1}</a>", textLink, textLink.OriginalInput) :
textLink.OriginalInput;
});
return result;
}
测试用例:
[TestMethod]
public void RegexUtil_TextLink_Parsing()
{
Assert.IsTrue(new TextLink("smthing.com").Valid);
Assert.IsTrue(new TextLink("www.smthing.com/").Valid);
Assert.IsTrue(new TextLink("http://smthing.com").Valid);
Assert.IsTrue(new TextLink("http://www.smthing.com").Valid);
Assert.IsTrue(new TextLink("http://www.smthing.com/").Valid);
Assert.IsTrue(new TextLink("http://www.smthing.com/publisher").Valid);
// port
Assert.IsTrue(new TextLink("http://www.smthing.com:80").Valid);
Assert.IsTrue(new TextLink("http://www.smthing.com:80/").Valid);
// https
Assert.IsTrue(new TextLink("https://smthing.com").Valid);
Assert.IsFalse(new TextLink("").Valid);
Assert.IsFalse(new TextLink("smthing.com.").Valid);
Assert.IsFalse(new TextLink("smthing.com-").Valid);
}
[TestMethod]
public void RegexUtil_TextLink_ToString()
{
// default
Assert.AreEqual("http://www.smthing.com", new TextLink("smthing.com").ToString());
Assert.AreEqual("http://www.smthing.com", new TextLink("http://www.smthing.com").ToString());
Assert.AreEqual("http://www.smthing.com/", new TextLink("smthing.com/").ToString());
Assert.AreEqual("https://www.smthing.com", new TextLink("https://www.smthing.com").ToString());
}
于 2015-02-25T12:51:28.213 回答
0
这对我有用:
str = Regex.Replace(str,
@"((http|ftp|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?)",
"<a target='_blank' href='$1'>$1</a>");
于 2019-04-11T12:03:34.003 回答