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我正在搜索一个包含 25 列以上的表。其中两个是名字和姓氏。我可以让 CONCAT 单独搜索它们，但是当我添加其他 OR 选择时，我会出错。谁能指出我正确的方向？任何帮助都会很棒。更多详细信息：我想在这里解决这个问题。我有两个运行良好的不同 SELECT 语句 #1 是

$query = "SELECT `CustomerID`, `CompanyName`, `ContactFirstName`, `ContactLastName`,
`BillingAddress`, `BillingAddress2`, `City`, `PostalCode`, `PhoneNumber`, `FaxNumber`, `EMail`
FROM `Customers` WHERE `CustomerID` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `CompanyName` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `ContactFirstName` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `ContactLastName` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `BillingAddress` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `BillingAddress2` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `PhoneNumber` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `EMail` LIKE '%".mysql_real_escape_string($search_text)."%'";

#2 是

SELECT *, CONCAT_WS(' ',ContactFirstName,ContactLastName) AS FullName FROM `Customers` HAVING
FullName LIKE '%".mysql_real_escape_string($search_text)."%'";

我一直无法弄清楚如何将第二个选择添加到第一个中。

--- 编辑--- 在 a1ex07 的帖子之后，我重新进行了查询，并且它以我正在寻找的方式工作......

$query = "SELECT `CustomerID`, `CompanyName`, `ContactFirstName`, `ContactLastName`, 
BillingAddress`, `BillingAddress2`, `City`,  `PostalCode`, `PhoneNumber`, `FaxNumber`, `EMail`
FROM `Customers`
WHERE `CustomerID` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `CompanyName` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `BillingAddress` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `BillingAddress2` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `City` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `PostalCode` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `PhoneNumber` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `FaxNumber` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `EMail` LIKE '%".mysql_real_escape_string($search_text)."%'
OR CONCAT_WS(' ',ContactFirstName,ContactLastName) LIKE 
'%".mysql_real_escape_string($search_text)."%'";

$query_run = mysql_query($query);
while ($query_row = mysql_fetch_assoc($query_run)) {
$CustomerID = $query_row['CustomerID'];
$CompanyName = $query_row['CompanyName'];
$ContactFirstName = $query_row['ContactFirstName'];
$ContactLastName = $query_row['ContactLastName'];
$BillingAddress = $query_row['BillingAddress'];
$BillingAddress2 = $query_row['BillingAddress2'];
$City = $query_row['City'];
$PostalCode = $query_row['PostalCode'];
$PhoneNumber = $query_row['PhoneNumber'];
$FaxNumber = $query_row['FaxNumber'];
$EMail = $query_row['EMail'];

echo $CustomerID.' '.$CompanyName.' '.$ContactFirstName.' '.$ContactLastName.'
'.$BillingAddress.' '.$BillingAddress2.' '.$City.' '.$PostalCode.' '.$PhoneNumber.' 
'.$FaxNumber.' '.$EMail.'<br>';

它似乎正在做我想做的事，除非有办法让FullName变量重新进入？

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2 回答 2

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在#1 上，如果你在单引号后面加一个空格怎么办？' "; 换句话说，这样你的 sql 就不会一起运行，适当的间距。

另外，回显您的 SQL 并尝试查看它。

于 2011-09-27T16:22:47.173 回答
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如果我理解你，你正在尝试添加WHERE ... OR FullName LIKE ...到第一个查询。它失败了，因为您不能在WHERE. 你需要做WHERE ... OR CONCAT_WS(' ',ContactFirstName,ContactLastName) LIKE ....

更新：

它似乎在做我想做的事，除非有办法让 FullName 变量重新输入？

只需将其添加到SELECT: SELECT ..., CONCAT_WS(' ',ContactFirstName,ContactLastName) AS FullName。

再一次，问题是别名不能用于WHERE. 有一些方法可以处理它：

  1. 在 中使用表达式WHERE：SELECT ..., CONCAT_WS(' ',ContactFirstName,ContactLastName) AS FullName WHERE ... OR CONCAT_WS(' ',ContactFirstName,ContactLastName)
  2. 在中使用别名HAVING：SELECT ..., CONCAT_WS(' ',ContactFirstName,ContactLastName) AS FullName WHERE ... HAVING FullName ...
  3. 使用派生表：
    SELECT * FROM ( SELECT ..., CONCAT_WS(' ',ContactFirstName,ContactLastName) AS FullName
    ...)a
    WHERE ... OR FullName ....

您的最终查询应如下所示：

    $query = "SELECT `CustomerID`, `CompanyName`, `ContactFirstName`, `ContactLastName`, 
BillingAddress`, `BillingAddress2`, `City`,  `PostalCode`, 
 `PhoneNumber`, `FaxNumber`, `EMail`,  
 CONCAT_WS(' ',ContactFirstName,ContactLastName) AS FullName
FROM `Customers`
WHERE `CustomerID` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `CompanyName` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `BillingAddress` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `BillingAddress2` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `City` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `PostalCode` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `PhoneNumber` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `FaxNumber` LIKE '%".mysql_real_escape_string($search_text)."%'
OR `EMail` LIKE '%".mysql_real_escape_string($search_text)."%'
OR CONCAT_WS(' ',ContactFirstName,ContactLastName) LIKE 
'%".mysql_real_escape_string($search_text)."%'";
于 2011-09-27T16:05:51.753 回答