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我需要一个非常准确的计算器公式。现在我的公式适用于每月复利的每月供款,但是当您使用每月复利的每周供款时,我不知道如何调整公式。您可以通过下载和解压缩附件来查看我的计算器。

到目前为止,这是我在网上找到的最准确的计算器。如果我能得到一个 Javascript 公式来匹配这个计算器生成的值,我会很高兴。

每周供款和每月复利的问题在于,虽然一年有 52 周,但有些月有 5 周,有些月有 4 周。我认为他们的计算器没有考虑到这一点。我认为他们只是根据 52 周来计算,每 4 周他们复利一次。

这是我正在使用的公式:

var P = startingAmount;
var Y = yearsOfInvesting;
var c = getAdditionalContributionsPerPeriod;
var t = getTermsPerPeriod;
var n = t * Y;
var r = interestRate / 100 / t; // interestRate [%]
var z = 1 + r;
total = P * Math.pow(z, n) + c * (Math.pow(z, n + 1) - z) / r;

给定一个场景

  • 本金 1000 美元,
  • 每周50美元的捐款,
  • 10年,
  • 每月复利,

另一个计算器说total应该是 30,007 美元,四舍五入。我最接近这一点的是使用这个公式是每周贡献和每周复利(但我想要每月复利!):

var P = 1000;//startingAmount;
var Y = 0;//yearsOfInvesting;
var c = 50;//
var n = 520;//t * Y;
var r = .02/52;
var z = 1 + r;

mz = P * Math.pow(z, n) + c * (Math.pow(z, n + 1) - z) / r;
document.write(mz);

如何使我的公式适用于每周和每日捐款?

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1 回答 1

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嗯......这两个都与那个计算器略有不同,但可能更准确地了解事情的实际完成方式(但是不确定,因为我不知道它实际上是如何完成的):

function calc( startingAmount, yearsOfInvesting, additionalContributionsPerPeriod, interestRate ) {
    var interestPerDay = ( interestRate / 365 );
    var total = startingAmount;
    var date = new Date( new Date().getFullYear() + new Date().getMonth() + 1, 1 );
    var endDate = new Date( date.getFullYear() + yearsOfInvesting, date.getMonth(), date.getDate() - 1 );
    var startingWeekday = date.getDay();
    var startingDate = date.getDate();
    var runningInterest = 0;
    while( Date.parse( date.toString() ) < Date.parse( endDate.toString() ) ) {
        date.setDate( date.getDate() + 1 );
        runningInterest = runningInterest + total * interestPerDay;
        if( date.getDay() == startingWeekday ) {
            total = total + additionalContributionsPerPeriod;
        }
        if( date.getDate() == startingDate ) {
            total = total + runningInterest;
            runningInterest = 0;
        }
    }
    total = total + runningInterest;
    return total;
}
function calc2( startingAmount, yearsOfInvesting, additionalContributionsPerPeriod, interestRate ) {
    var interestPerDay = ( interestRate / 365 );
    var total = startingAmount;
    var runningInterest = 0;
    for( var day = 1; day <= 365 * yearsOfInvesting; day++ ) {
        runningInterest = runningInterest + total * interestPerDay;
        if( day % 7 == 0 ) {
            total = total + additionalContributionsPerPeriod;
        }
        if( day % 30 == 0 ) {
            total = total + runningInterest;
            runningInterest = 0;
        }
    }
    total = total + runningInterest;
    return total;
}
document.write( 3647 + "<br>" + calc( 1000, 1, 50, 0.02 ) + "<br>" + calc2( 1000, 1, 50, 0.02 ) );
document.write( "<br><br>" );
document.write( 6347 + "<br>" + calc( 1000, 2, 50, 0.02 ) + "<br>" + calc2( 1000, 2, 50, 0.02 ) );
document.write( "<br><br>" );
document.write( 14779 + "<br>" + calc( 1000, 5, 50, 0.02 ) + "<br>" + calc2( 1000, 5, 50, 0.02 ) );
document.write( "<br><br>" );
document.write( 30007 + "<br>" + calc( 1000, 10, 50, 0.02 ) + "<br>" + calc2( 1000, 10, 50, 0.02 ) );
document.write( "<br><br>" );
document.write( 31673 + "<br>" + calc( 1000, 10, 50, 0.03 ) + "<br>" + calc2( 1000, 10, 50, 0.03 ) );
document.write( "<br><br>" );
document.write( 33460 + "<br>" + calc( 1000, 10, 50, 0.04 ) + "<br>" + calc2( 1000, 10, 50, 0.04 ) );
document.write( "<br><br>" );
document.write( 35378 + "<br>" + calc( 1000, 10, 50, 0.05 ) + "<br>" + calc2( 1000, 10, 50, 0.05 ) );
document.write( "<br><br>" );
document.write( 772849953 + "<br>" + calc( 1000, 55, 50, 0.20 ) + "<br>" + calc2( 1000, 55, 50, 0.20 ) );
于 2009-04-21T20:21:00.163 回答