null - 卡洛克简单问题

Question

char* lw;
if((lw=(char *)calloc(2, sizeof(char))==0)) 
   printf("Failed to allocate.\n"); 
else 
   printf("allocated %p\n", lw);

我已经阅读了 calloc 的手册，需要一个快速而简短的答案，为什么它输出 NIL？它转到else，所以lw不可能是NIL，然后输出“已分配（nil）”？上帝之手？;)

Answer 1

Because you are assigning to lw calloc(...) == 0, which is false. You want it the other way around

Replace ==0)) with )==NULL).