如何在 C# 中转换十六进制数和十进制数？
Andy McCluggage
问问题
398294 次
20 回答
317
要将十进制转换为十六进制，请...
string hexValue = decValue.ToString("X");
要将十六进制转换为十进制，请执行以下任一操作...
int decValue = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);
或者
int decValue = Convert.ToInt32(hexValue, 16);
于 2008-09-16T16:26:00.587 回答
63
十六进制 -> 十进制：
Convert.ToInt64(hexValue, 16);
十进制 -> 十六进制
string.format("{0:x}", decValue);
于 2008-09-16T16:23:13.060 回答
28
看起来你可以说
Convert.ToInt64(value, 16)
从十六进制中获取十进制。
另一种方法是：
otherVar.ToString("X");
于 2008-09-16T16:22:03.420 回答
13
如果您希望在从十六进制数转换为十进制数时获得最佳性能，您可以使用预先填充的十六进制到十进制值表的方法。
这是说明该想法的代码。我的性能测试表明它可以比 Convert.ToInt32(...) 快 20%-40%：
class TableConvert
{
static sbyte[] unhex_table =
{ -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,-1,-1,-1,-1,-1,-1
,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
};
public static int Convert(string hexNumber)
{
int decValue = unhex_table[(byte)hexNumber[0]];
for (int i = 1; i < hexNumber.Length; i++)
{
decValue *= 16;
decValue += unhex_table[(byte)hexNumber[i]];
}
return decValue;
}
}
于 2012-02-03T09:57:04.823 回答
12
// Store integer 182
int decValue = 182;
// Convert integer 182 as a hex in a string variable
string hexValue = decValue.ToString("X");
// Convert the hex string back to the number
int decAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);
于 2008-09-16T16:22:49.207 回答
2
String stringrep = myintvar.ToString("X");
int num = int.Parse("FF", System.Globalization.NumberStyles.HexNumber);
于 2008-09-16T16:21:54.810 回答
2
十六进制到十进制转换
Convert.ToInt32(number, 16);
十进制到十六进制转换
int.Parse(number, System.Globalization.NumberStyles.HexNumber)
于 2017-05-22T19:20:05.737 回答
2
尝试在 C# 中使用 BigNumber - 表示任意大的有符号整数。
程序
using System.Numerics;
...
var bigNumber = BigInteger.Parse("837593454735734579347547357233757342857087879423437472347757234945743");
Console.WriteLine(bigNumber.ToString("X"));
输出
4F30DC39A5B10A824134D5B18EEA3707AC854EE565414ED2E498DCFDE1A15DA5FEB6074AE248458435BD417F06F674EB29A2CFECF
可能的例外，
ArgumentNullException - 值为 null。
FormatException - 值的格式不正确。
结论
您可以转换字符串并将值存储在 BigNumber 中，而不受数字大小的限制，除非字符串为空且非字母表
于 2018-03-30T06:54:52.523 回答
1
static string chex(byte e) // Convert a byte to a string representing that byte in hexadecimal
{
string r = "";
string chars = "0123456789ABCDEF";
r += chars[e >> 4];
return r += chars[e &= 0x0F];
} // Easy enough...
static byte CRAZY_BYTE(string t, int i) // Take a byte, if zero return zero, else throw exception (i=0 means false, i>0 means true)
{
if (i == 0) return 0;
throw new Exception(t);
}
static byte hbyte(string e) // Take 2 characters: these are hex chars, convert it to a byte
{ // WARNING: This code will make small children cry. Rated R.
e = e.ToUpper(); //
string msg = "INVALID CHARS"; // The message that will be thrown if the hex str is invalid
byte[] t = new byte[] // Gets the 2 characters and puts them in seperate entries in a byte array.
{ // This will throw an exception if (e.Length != 2).
(byte)e[CRAZY_BYTE("INVALID LENGTH", e.Length ^ 0x02)],
(byte)e[0x01]
};
for (byte i = 0x00; i < 0x02; i++) // Convert those [ascii] characters to [hexadecimal] characters. Error out if either character is invalid.
{
t[i] -= (byte)((t[i] >= 0x30) ? 0x30 : CRAZY_BYTE(msg, 0x01)); // Check for 0-9
t[i] -= (byte)((!(t[i] < 0x0A)) ? (t[i] >= 0x11 ? 0x07 : CRAZY_BYTE(msg, 0x01)) : 0x00); // Check for A-F
}
return t[0x01] |= t[0x00] <<= 0x04; // The moment of truth.
}
于 2010-03-20T18:39:55.357 回答
1
这并不是最简单的方法，但此源代码使您能够正确任何类型的八进制数，即 23.214、23 和 0.512 等。希望对你有帮助..
public string octal_to_decimal(string m_value)
{
double i, j, x = 0;
Int64 main_value;
int k = 0;
bool pw = true, ch;
int position_pt = m_value.IndexOf(".");
if (position_pt == -1)
{
main_value = Convert.ToInt64(m_value);
ch = false;
}
else
{
main_value = Convert.ToInt64(m_value.Remove(position_pt, m_value.Length - position_pt));
ch = true;
}
while (k <= 1)
{
do
{
i = main_value % 10; // Return Remainder
i = i * Convert.ToDouble(Math.Pow(8, x)); // calculate power
if (pw)
x++;
else
x--;
o_to_d = o_to_d + i; // Saving Required calculated value in main variable
main_value = main_value / 10; // Dividing the main value
}
while (main_value >= 1);
if (ch)
{
k++;
main_value = Convert.ToInt64(Reversestring(m_value.Remove(0, position_pt + 1)));
}
else
k = 2;
pw = false;
x = -1;
}
return (Convert.ToString(o_to_d));
}
于 2010-12-17T21:40:48.447 回答
1
如果它是一个超出正常整数容量的非常大的十六进制字符串：
对于 .NET 3.5，我们可以使用 BouncyCastle 的 BigInteger 类：
String hex = "68c7b05d0000000002f8";
// results in "494809724602834812404472"
String decimal = new Org.BouncyCastle.Math.BigInteger(hex, 16).ToString();
.NET 4.0 有BigInteger类。
于 2011-06-01T17:47:18.980 回答
1
这个对我有用：
public static decimal HexToDec(string hex)
{
if (hex.Length % 2 == 1)
hex = "0" + hex;
byte[] raw = new byte[hex.Length / 2];
decimal d = 0;
for (int i = 0; i < raw.Length; i++)
{
raw[i] = Convert.ToByte(hex.Substring(i * 2, 2), 16);
d += Math.Pow(256, (raw.Length - 1 - i)) * raw[i];
}
return d.ToString();
return d;
}
于 2021-05-22T18:28:16.667 回答
0
我的版本是我认为更容易理解的，因为我的 C# 知识不是那么高。我正在使用这个算法：http ://easyguyevo.hubpages.com/hub/Convert-Hex-to-Decimal （示例2）
using System;
using System.Collections.Generic;
static class Tool
{
public static string DecToHex(int x)
{
string result = "";
while (x != 0)
{
if ((x % 16) < 10)
result = x % 16 + result;
else
{
string temp = "";
switch (x % 16)
{
case 10: temp = "A"; break;
case 11: temp = "B"; break;
case 12: temp = "C"; break;
case 13: temp = "D"; break;
case 14: temp = "E"; break;
case 15: temp = "F"; break;
}
result = temp + result;
}
x /= 16;
}
return result;
}
public static int HexToDec(string x)
{
int result = 0;
int count = x.Length - 1;
for (int i = 0; i < x.Length; i++)
{
int temp = 0;
switch (x[i])
{
case 'A': temp = 10; break;
case 'B': temp = 11; break;
case 'C': temp = 12; break;
case 'D': temp = 13; break;
case 'E': temp = 14; break;
case 'F': temp = 15; break;
default: temp = -48 + (int)x[i]; break; // -48 because of ASCII
}
result += temp * (int)(Math.Pow(16, count));
count--;
}
return result;
}
}
class Program
{
static void Main(string[] args)
{
Console.Write("Enter Decimal value: ");
int decNum = int.Parse(Console.ReadLine());
Console.WriteLine("Dec {0} is hex {1}", decNum, Tool.DecToHex(decNum));
Console.Write("\nEnter Hexadecimal value: ");
string hexNum = Console.ReadLine().ToUpper();
Console.WriteLine("Hex {0} is dec {1}", hexNum, Tool.HexToDec(hexNum));
Console.ReadKey();
}
}
于 2015-02-09T10:58:40.927 回答
0
将二进制转换为十六进制
Convert.ToString(Convert.ToUInt32(binary1, 2), 16).ToUpper()
于 2015-04-29T09:35:24.167 回答
0
您可以使用此代码并可能设置十六进制长度和部分：
const int decimal_places = 4;
const int int_places = 4;
static readonly string decimal_places_format = $"X{decimal_places}";
static readonly string int_places_format = $"X{int_places}";
public static string DecimaltoHex(decimal number)
{
var n = (int)Math.Truncate(number);
var f = (int)Math.Truncate((number - n) * ((decimal)Math.Pow(10, decimal_places)));
return $"{string.Format($"{{0:{int_places_format}}}", n)}{string.Format($"{{0:{decimal_places_format}}}", f)}";
}
public static decimal HextoDecimal(string number)
{
var n = number.Substring(0, number.Length - decimal_places);
var f = number.Substring(number.Length - decimal_places);
return decimal.Parse($"{int.Parse(n, System.Globalization.NumberStyles.HexNumber)}.{int.Parse(f, System.Globalization.NumberStyles.HexNumber)}");
}
于 2021-04-09T05:42:06.403 回答
0
十进制 - 六进制
var decValue = int.Parse(Console.ReadLine());
string hex = string.Format("{0:x}", decValue);
Console.WriteLine(hex);
Hexa - 十进制（使用命名空间：使用 System.Globalization；）
var hexval = Console.ReadLine();
int decValue = int.Parse(hexval, NumberStyles.HexNumber);
Console.WriteLine(decValue);
于 2021-07-05T12:44:27.180 回答
0
将 Hex 转换为 Dec 并返回的四种 C# 原生方法：
using System;
namespace Hexadecimal_and_Decimal
{
internal class Program
{
private static void Main(string[] args)
{
string hex = "4DEAD";
int dec;
// hex to dec:
dec = int.Parse(hex, System.Globalization.NumberStyles.HexNumber);
// or:
dec = Convert.ToInt32(hex, 16);
// dec to hex:
hex = dec.ToString("X"); // lowcase: x, uppercase: X
// or:
hex = string.Format("{0:X}", dec); // lowcase: x, uppercase: X
Console.WriteLine("Hexadecimal number: " + hex);
Console.WriteLine("Decimal number: " + dec);
}
}
}
于 2022-02-22T22:44:53.993 回答
-1
一种将字节数组转换为十六进制表示的扩展方法。这用前导零填充每个字节。
/// <summary>
/// Turns the byte array into its Hex representation.
/// </summary>
public static string ToHex(this byte[] y)
{
StringBuilder sb = new StringBuilder();
foreach (byte b in y)
{
sb.Append(b.ToString("X").PadLeft(2, "0"[0]));
}
return sb.ToString();
}
于 2011-07-12T15:27:55.800 回答
-1
这是我的功能：
using System;
using System.Collections.Generic;
class HexadecimalToDecimal
{
static Dictionary<char, int> hexdecval = new Dictionary<char, int>{
{'0', 0},
{'1', 1},
{'2', 2},
{'3', 3},
{'4', 4},
{'5', 5},
{'6', 6},
{'7', 7},
{'8', 8},
{'9', 9},
{'a', 10},
{'b', 11},
{'c', 12},
{'d', 13},
{'e', 14},
{'f', 15},
};
static decimal HexToDec(string hex)
{
decimal result = 0;
hex = hex.ToLower();
for (int i = 0; i < hex.Length; i++)
{
char valAt = hex[hex.Length - 1 - i];
result += hexdecval[valAt] * (int)Math.Pow(16, i);
}
return result;
}
static void Main()
{
Console.WriteLine("Enter Hexadecimal value");
string hex = Console.ReadLine().Trim();
//string hex = "29A";
Console.WriteLine("Hex {0} is dec {1}", hex, HexToDec(hex));
Console.ReadKey();
}
}
于 2014-01-12T20:00:19.580 回答
-1
我的解决方案有点像回归基础，但它无需使用任何内置函数即可在数字系统之间进行转换。
public static string DecToHex(long a)
{
int n = 1;
long b = a;
while (b > 15)
{
b /= 16;
n++;
}
string[] t = new string[n];
int i = 0, j = n - 1;
do
{
if (a % 16 == 10) t[i] = "A";
else if (a % 16 == 11) t[i] = "B";
else if (a % 16 == 12) t[i] = "C";
else if (a % 16 == 13) t[i] = "D";
else if (a % 16 == 14) t[i] = "E";
else if (a % 16 == 15) t[i] = "F";
else t[i] = (a % 16).ToString();
a /= 16;
i++;
}
while ((a * 16) > 15);
string[] r = new string[n];
for (i = 0; i < n; i++)
{
r[i] = t[j];
j--;
}
string res = string.Concat(r);
return res;
}
于 2019-01-07T22:50:55.337 回答