unicode-string - iPhone：将 Unicode 转换为字符串

Question

我需要将以下内容转换为字符串并显示

Overall, the \u2018\u2018typical\u2019\u2019 xyz is broadly expressed

我尝试了各种无码转换

NSData *asciiData = [desc dataUsingEncoding:NSASCIIStringEncoding   allowLossyConversion:YES]; 
NSString *encodedString = [[NSString alloc] initWithData:asciiData encoding:NSASCIIStringEncoding

和：

[NSString stringByReplacingOccurrencesOfString:@"\u2018" withString:@""]

没有成功。

请建议我解决此问题。

Answer 1

char cString[] = "\u2018\u2018typical\u2019\u2019";
NSString *string = [NSString stringWithCString:cString encoding:NSUTF8StringEncoding];
NSLog(@"string: %@", string);

NSLog 输出：字符串：''典型''</p>

或者

NSData *data = [NSData dataWithBytes:cString length:strlen(cString)];
NSString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"string: %@", string);

NSLog 输出：字符串：''典型''</p>