javascript - 从回调外部的回调中提取参数

Question

如何提取回调函数的参数（a，b）并将另一个参数（c）添加到函数调用？

function mycallback(a, b, c) {
  // do stuff with a, b, c
}

function perform(callback) {
  // I need to extract a and b here and add c:
  // ???
  //callback.apply(???);     
}

perform( function() { mycallback(1, 2) } );

Answer 1

我能想到的唯一方法是将参数传递给perform自身，然后让它传递给回调：

function perform(callback) {
  var args = Array.prototype.slice.apply(arguments).splice(1);
  // use args... add c with args.push(c)...
  callback.apply(this, args);
}

perform(mycallback, 1, 2);