1

尝试在 Massive 中执行以下查询时，为什么会出现运行时绑定程序异常？

  public dynamic Find(string email, string type)
    {
        dynamic result = new ExpandoObject();
        result = this.Query(@"SELECT * FROM Addresses a 
            INNER JOIN Members m ON m.Id = a.MemberId 
            INNER JOIN AddressType at ON at.Id = a.AddressTypeId 
            WHERE m.Email = @0 AND at.Type = @1", new {email, type});
        return result;
    }

编辑以显示解决方案：我需要更改我的查询以确保只返回一个名为“Id”的列。我收到绑定错误，因为成员和地址中的多个列有一个名为“Id”的列。要在我的查询中获得一个结果，我必须将其修改为：

result = this.Query(@"SELECT a.* FROM Addresses a 
            INNER JOIN Members m ON m.Id = a.MemberId 
            INNER JOIN AddressType at ON at.Id = a.AddressTypeId 
            WHERE m.Email = @0 AND at.Type = @1", new object[] { email, type }).Single();

希望这对其他人有帮助。

4

1 回答 1

2

您在匿名对象中传递参数，而不是对象数组（参数）。因此，它成为第一个参数并且无法绑定，因为您的查询需要 2 个参数。另外Query返回 type IEnumerable<dynamic>。

将您的代码更改为：

public dynamic Find(string email, string type)
{
    IEnumerable<dynamic> result;
    result = this.Query(@"SELECT a.* FROM Addresses a 
        INNER JOIN Members m ON m.Id = a.MemberId 
        INNER JOIN AddressType at ON at.Id = a.AddressTypeId 
        WHERE m.Email = @0 AND at.Type = @1", email, type);

    // decide how you want to handle multiple results here
    return result.FirstOrDefault();
}

或者您可以使用显式对象数组：

        WHERE m.Email = @0 AND at.Type = @1", new object[] {email, type});
于 2011-09-10T19:14:51.517 回答