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让我先说一句：我是一名 PHP 黑客。这里可能有一些愚蠢的错误。如果您看到它们，请指出它们。

我正在尝试做的事情：我正在为一家餐厅创建一个页面，该页面希望显示他们的 Yelp 评论。我正在使用 Yelp Phone API 来获取特定业务的评论。请查看位于此处的 Yelp API 文档的示例响应：http ://www.yelp.com/developers/documentation/phone_api#sampleResponse

我做了什么：

  • 成功连接API并返回响应
  • 在 foreach 循环中从响应数组中回显值。

如果您查看文档，您可以看到响应的几个级别。我可以轻松地打印、回显来自第二层的任何值，但我真正想要的是全部嵌套在响应的“评论”部分中。我无法弄清楚如何在评论部分中回显这些值（例如 user_name、review_excerpt 等）。

我的代码：

$yelpstring = file_get_contents("http://api.yelp.com/phone_search?phone=[redactedphonenumber]&ywsid=[redactedapikey]", true);
$obj = json_decode($yelpstring);

foreach($obj->businesses as $key => $business)
{
$reviews = $business->reviews;

//print_r($reviews);
echo $reviews['user_name'];
}

如果我回显 $reviews，我只会得到“数组”这个词。如果我 print_r($reviews)，我会得到一个预期的键和值列表。如果我尝试从数组中回显特定值（echo $reviews ['user_name']，我什么也得不到。任何关于我做错的事情的线索将不胜感激。我确定我错过了一些简单的东西。 感谢您的时间！

编辑： print_r($reviews) 输出：

Array ( [0] => stdClass Object ( [rating_img_url_small] => http://media4.px.yelpcdn.com/static/201012164278297776/img/ico/stars/stars_small_2.png [user_photo_url_small] => http://media2.px.yelpcdn.com/static/201012162819681786/img/gfx/blank_user_extra_small.gif [rating_img_url] => http://media4.px.yelpcdn.com/static/201012163489049252/img/ico/stars/stars_2.png [rating] => 2 [user_url] => http://www.yelp.com/user_details?userid=vZbcPrYPSMFIDIfTub5H1g [url] => http://www.yelp.com/biz/jelly-cafe-denver#hrid:u9ckRV6tKApe6Bu93M93CA [mobile_uri] => http://m.yelp.com/biz/5G2X2q9p7QFdm-LbyutltQ?srid=u9ckRV6tKApe6Bu93M93CA [text_excerpt] => I wanted to like this place. It's got the contemporary name and it's full of hipsters. The place looked clean and the style was fun and cute. I felt like... [user_photo_url] => http://media3.px.yelpcdn.com/static/201012161186834854/img/gfx/blank_user_small.gif [date] => 2011-09-07 [user_name] => boycott p. [id] => u9ckRV6tKApe6Bu93M93CA ) [1] => stdClass Object ( [rating_img_url_small] => http://media4.px.yelpcdn.com/static/201012164278297776/img/ico/stars/stars_small_2.png [user_photo_url_small] => http://media1.px.yelpcdn.com/upthumb/MWu84G5QtmBmT9GoqjT_kg/ss [rating_img_url] => http://media4.px.yelpcdn.com/static/201012163489049252/img/ico/stars/stars_2.png [rating] => 2 [user_url] => http://www.yelp.com/user_details?userid=izF2cGrmqt-u_Z2tDZ8dbg [url] => http://www.yelp.com/biz/jelly-cafe-denver#hrid:OYLeeCMgnpZkk1c9LWu97g [mobile_uri] => http://m.yelp.com/biz/5G2X2q9p7QFdm-LbyutltQ?srid=OYLeeCMgnpZkk1c9LWu97g [text_excerpt] => Food is decent and overpriced, but service is a joke. Your food will take a minimum of 20 minutes, for the basic breakfast. Then when your food does come... [user_photo_url] => http://media1.px.yelpcdn.com/upthumb/MWu84G5QtmBmT9GoqjT_kg/ms [date] => 2011-09-06 [user_name] => April H. [id] => OYLeeCMgnpZkk1c9LWu97g ) [2] => stdClass Object ( [rating_img_url_small] => http://media2.px.yelpcdn.com/static/20101216418129184/img/ico/stars/stars_small_4.png [user_photo_url_small] => http://media1.px.yelpcdn.com/upthumb/3euzdGdLZRFxImY68MSg7w/ss [rating_img_url] => http://media2.px.yelpcdn.com/static/201012164084228337/img/ico/stars/stars_4.png [rating] => 4 [user_url] => http://www.yelp.com/user_details?userid=bHR9UU4vtx2QKZD44O0E5g [url] => http://www.yelp.com/biz/jelly-cafe-denver#hrid:njvNAzfSII3PxXyUymLZ1w [mobile_uri] => http://m.yelp.com/biz/5G2X2q9p7QFdm-LbyutltQ?srid=njvNAzfSII3PxXyUymLZ1w [text_excerpt] => Stopped here for breakfast on a friday morning. We were seated immediately and had a really friendly waitress. I ordered a side order of the Chai french... [user_photo_url] => http://media1.px.yelpcdn.com/upthumb/3euzdGdLZRFxImY68MSg7w/ms [date] => 2011-09-05 [user_name] => Diane F. [id] => njvNAzfSII3PxXyUymLZ1w ) )
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2 回答 2

1

$reviews是审查对象的数组。您需要遍历它以获取您所追求的数据。

于 2011-09-09T17:26:12.443 回答
1

根据 print_r 的输出，您无法引用 $reviews['user_name'];

注意 $reviews 是一个对象数组。所以要访问 user_name 你需要使用

echo $reviews[0]->user_name;

如果数组中有多个项目，则需要一个循环，例如

for ($i = 0; $i<count($reviews); $i++) {
    echo $reviews[$i]->user_name;
}

我希望这有帮助。

于 2011-09-09T19:04:32.510 回答