28

在 C# 中,如何将 Unix 样式的时间戳转换为 yyyy-MM-ddThh:mm:ssZ?

4

9 回答 9

33

首先将您的毫秒转换为TimeSpan

var time = TimeSpan.FromMilliseconds(milliseconds);

现在,在 .NET 4 中,您可以.ToString()使用格式字符串参数进行调用。请参阅http://msdn.microsoft.com/en-us/library/system.timespan.tostring.aspx

在以前版本的 .NET 中,您必须从 TimeSpan 的属性手动构造格式化字符串。

于 2011-09-07T16:05:58.433 回答
24

新日期时间(numTicks * 10000)

DateTime(long ticks)构造函数是您所需要的。每个刻度代表 100 纳秒,因此乘以 10000 得到 1 毫秒。

于 2011-09-07T16:04:14.897 回答
20

如果毫秒基于UNIX 纪元时间,那么您可以使用:

var posixTime = DateTime.SpecifyKind(new DateTime(1970, 1, 1), DateTimeKind.Utc);
var time = posixTime.AddMilliseconds(milliSecs);
于 2014-06-28T07:02:02.103 回答
9

这对我有用:

DateTimeOffset.FromUnixTimeMilliseconds(milliseconds);

如果需要,您可以从中获取 DateTime。

于 2017-05-24T18:04:23.913 回答
4

干得好:

public static class UnixDateTime
    {
        public static DateTimeOffset FromUnixTimeSeconds(long seconds)
        {
            if (seconds < -62135596800L || seconds > 253402300799L)
                throw new ArgumentOutOfRangeException("seconds", seconds, "");

            return new DateTimeOffset(seconds * 10000000L + 621355968000000000L, TimeSpan.Zero);
        }

        public static DateTimeOffset FromUnixTimeMilliseconds(long milliseconds)
        {
            if (milliseconds < -62135596800000L || milliseconds > 253402300799999L)
                throw new ArgumentOutOfRangeException("milliseconds", milliseconds, "");

            return new DateTimeOffset(milliseconds * 10000L + 621355968000000000L, TimeSpan.Zero);
        }

        public static long ToUnixTimeSeconds(this DateTimeOffset utcDateTime)
        {
            return utcDateTime.Ticks / 10000000L - 62135596800L;
        }

        public static long ToUnixTimeMilliseconds(this DateTimeOffset utcDateTime)
        {
            return utcDateTime.Ticks / 10000L - 62135596800000L;
        }

        [Test]
        public void UnixSeconds()
        {
            DateTime utcNow = DateTime.UtcNow;
            DateTimeOffset utcNowOffset = new DateTimeOffset(utcNow);

            long unixTimestampInSeconds = utcNowOffset.ToUnixTimeSeconds();

            DateTimeOffset utcNowOffsetTest = UnixDateTime.FromUnixTimeSeconds(unixTimestampInSeconds);

            Assert.AreEqual(utcNowOffset.Year, utcNowOffsetTest.Year);
            Assert.AreEqual(utcNowOffset.Month, utcNowOffsetTest.Month);
            Assert.AreEqual(utcNowOffset.Date, utcNowOffsetTest.Date);
            Assert.AreEqual(utcNowOffset.Hour, utcNowOffsetTest.Hour);
            Assert.AreEqual(utcNowOffset.Minute, utcNowOffsetTest.Minute);
            Assert.AreEqual(utcNowOffset.Second, utcNowOffsetTest.Second);
        }

        [Test]
        public void UnixMilliseconds()
        {
            DateTime utcNow = DateTime.UtcNow;
            DateTimeOffset utcNowOffset = new DateTimeOffset(utcNow);

            long unixTimestampInMilliseconds = utcNowOffset.ToUnixTimeMilliseconds();

            DateTimeOffset utcNowOffsetTest = UnixDateTime.FromUnixTimeMilliseconds(unixTimestampInMilliseconds);

            Assert.AreEqual(utcNowOffset.Year, utcNowOffsetTest.Year);
            Assert.AreEqual(utcNowOffset.Month, utcNowOffsetTest.Month);
            Assert.AreEqual(utcNowOffset.Date, utcNowOffsetTest.Date);
            Assert.AreEqual(utcNowOffset.Hour, utcNowOffsetTest.Hour);
            Assert.AreEqual(utcNowOffset.Minute, utcNowOffsetTest.Minute);
            Assert.AreEqual(utcNowOffset.Second, utcNowOffsetTest.Second);
            Assert.AreEqual(utcNowOffset.Millisecond, utcNowOffsetTest.Millisecond);
        }
    }
于 2015-05-28T23:16:32.217 回答
3

此示例将演示一般概念,但您需要知道您的开始日期是 DateTime.MinValue 还是其他:

int ms = 1000;                          // One second
var date = new DateTime(ms * 10000);    // The constructor takes number of 100-nanoseconds ticks since DateTime.MinValue (midnight, january 1st, year 1)
string formatted = date.ToString("yyyy-MM-ddTHH:mm:ssZ");
Console.WriteLine(formatted);
于 2011-09-07T16:08:42.460 回答
1

您可以从 ticks构造您的日期时间:

long ticks = new DateTime(1979, 07, 28, 22, 35, 5, 
  new CultureInfo("en-US", false).Calendar).Ticks;
DateTime dt3 = new DateTime(ticks);
Console.Write(dt3.ToString("yyyy-MM-ddThh:mm:ssZ"));
于 2011-09-07T16:03:24.470 回答
0
    private static DateTime Milliseconds2Date(Double d)
    {         
        TimeSpan time = TimeSpan.FromMilliseconds(d);
        return new DateTime(1970, 1, 1) + time;
    }

    private static Double Date2Milliseconds(DateTime d)
    {

        var t = d.Subtract(new DateTime(1970, 1, 1));
        return t.TotalMilliseconds;            

    }
于 2018-12-15T10:47:42.773 回答
-5

这个问题应该有你需要的答案

简洁版本:

DateTime date = new DateTime(long.Parse(ticks));
date.ToString("yyyy-MM-ddThh:mm:ssZ");
于 2011-09-07T16:06:15.937 回答