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我正在写旅游博客的一部分，所以我有两个实体：地点和照片，与 1 对多相关，所以每个地方都可以有多张照片，但单张照片属于一个地方。

我的目标是创建摘要：最后添加了 3 个地方，并且每个地方我都想要一张照片（例如 ID 较低的照片，没关系）。重要的是不仅要有照片的 id，还有更多信息（列），如照片标签、照片路径等。

在 MS SQL 2008 中使用 SQL 可以通过使用 rank 函数来完成：

select top 3 * from
(
SELECT     p.id, p.label, p.VisitDate, ph.id AS photo_id, ph.Label, ph.Path,
RANK() OVER (PARTITION BY p.id ORDER BY ph.id) AS _rank
FROM         place AS p INNER JOIN
                      photo AS ph ON p.id = ph.place_id
) ranked
where _rank = 1
order by VisitDate desc

或者不用排名也可以解决：

SELECT     TOP (3) a.id AS ida, z.id AS idz, z.etykieta, z.sciezka, a.data_odwiedzenia
FROM         place AS a INNER JOIN
                      photo AS z ON a.id = z.id_atrakcji
and z.id in 
(
SELECT  min(z.id) AS idz
FROM photo z 
where z.id_atrakcji in (select top 3 a.id from place a order by a.data_dodania desc)
group by z.id_atrakcji
)
ORDER BY a.data_odwiedzenia DESC

我开始写这个查询没有排名，但我卡住了。

    summaryList =
 session.QueryOver(() => placeAlias)
.JoinAlias(o => o.Photos, () => photoAlias)
.SelectList(list => list
.Select(() => placeAlias.Id).WithAlias(() => summaryAlias.PlaceId)
.Select(() => placeAlias.Etykieta).WithAlias(() => summaryAlias.PlaceName)
.Select(() => photoAlias.Etykieta).WithAlias(() => summaryAlias.PhotoLabel)
.Select(() => photoAlias.Id).WithAlias(() => summaryAlias.PhotoId)
)
.OrderByAlias(() => placeAlias.VisitDate).Desc
.WithSubquery.WhereProperty(x => x.Id).In(lastPlaces)
.TransformUsing(Transformers.AliasToBean<PlacesSummary>())
.List<PlacesSummary>();

你能帮我解决这个问题吗？如何编写 lastPlaces queryover 或者可能有另一种方法？

问候， 麦科

4

2 回答 2

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var subquery = QueryOver.Of(() => photoAlias)
    .Where(photo => photo.Place.Id == placeAlias.Id)
    .Select(Projections.Max<Photo>(photo => photo.Id));

var summaryList = session.QueryOver(() => placeAlias)
    .OrderBy(() => placeAlias.VisitDate).Desc
    .JoinQueryOver(() => placeAlias.Photos, () => photoAlias)
    .WithSubquery.WhereProperty(photo => photo.Id).Eq(subquery)
    .SelectList(list => list
        .Select(() => placeAlias.Id).WithAlias(() => summaryAlias.PlaceId)
        .Select(() => placeAlias.Etykieta).WithAlias(() => summaryAlias.PlaceName)
        .Select(() => photoAlias.Etykieta).WithAlias(() => summaryAlias.PhotoLabel)
        .Select(() => photoAlias.Id).WithAlias(() => summaryAlias.PhotoId)
    )
    .TransformUsing(Transformers.AliasToBean<PlacesSummary>())
    .List<PlacesSummary>();

现在不能测试

于 2011-09-07T15:47:02.520 回答
0

它不能正常工作，但是您非常接近：

summaryList =
session.QueryOver(() => placeAlias)
.OrderByAlias(() => placeAlias.VisitDate).Desc
.JoinAlias(o => o.Photos, () => photoAlias)
**.WithSubquery.WhereProperty(()=> photoAlias.Id).Eq(subquery)**
.SelectList(list => list
.Select(() => placeAlias.Id).WithAlias(() => summaryAlias.PlaceId)
.Select(() => placeAlias.Etykieta).WithAlias(() => summaryAlias.PlaceName)
.Select(() => photoAlias.Etykieta).WithAlias(() => summaryAlias.PhotoLabel)
.Select(() => photoAlias.Id).WithAlias(() => summaryAlias.PhotoId))
.TransformUsing(Transformers.AliasToBean<PlacesSummary>())
.Take(3)
.List<PlacesSummary>();

它仅在一行中有所不同。WithSubquery 最初 它指的是 Place，而不是它应该指的是 Photo。现在它正在工作，它会生成以下 SQL：

SELECT TOP (3)  this_.id as y0_, this_.PlaceName as y1_, photoalias1_.PhotoName as y2_, photoalias1_.id as y3_ 
FROM [place] this_ inner join [photo] photoalias1_ on this_.id=photoalias1_.id_place 
WHERE photoalias1_.id = (SELECT min(this_0_.id) as y0_ FROM [photo] this_0_ WHERE this_0_.id_place = this_.id) 
ORDER BY this_.DateVisit desc

它工作得很好，但我还有另一个问题：

如何在 QueryOver 这样的 SQL 中重写：

SELECT  min(id)
FROM photo
where id in (... it doesn't matter what's here ...)
group by place_id

所以我只想要照片 id 的列表（只有列），这个查询将在另一个查询中用作子查询。可以通过 QueryOver 语法来完成吗？

于 2011-09-08T08:03:16.697 回答