0 
<?php $uploadNeed=3 ; for($i=0;$i<$uploadNeed;$i++) { ?>
    <div class="smWidth">
        <input type="file" name="upload_file" value="" id=" " OnClick="alert("
        2 ");" />
        <br />
        <div class="clear">
        </div>
    </div>
    <?php } ?>

我可以创建三个文件上传字段，但我只想在选择文件时添加一个新的输入文件......它应该继续增加......像Facebook风格的文件上传，你选择一个文件对于第一个字段，然后是下一个弹出窗口......

我实际上正在检查浏览的点击事件，但它不起作用......

4

2 回答 2

1

这是一个非常基本的纯 JS 实现——希望它能让你朝着正确的方向轻推……

<script type="text/javascript">

  // This keeps track of how many inputs there are, because each one MUST have a unique name!
  var inputCounter = 1;

  function inputChange() {

    // This function will add a new input element, in a div, as it is in your
    // original code, every time it is called. We attach it to the onchange
    // event of all the inputs

    // Declare local variables and increment input counter (for input names)
    var newContainerDiv, newClearDiv, newInput, newBr;
    inputCounter++;

    // Create the new elements and set their properties
    newContainerDiv = document.createElement('div');
    newContainerDiv.className = 'smWidth';
    newInput = document.createElement('input');
    newInput.type = 'file';
    newInput.name = 'upload_file_'+inputCounter;
    newInput.onchange = inputChange;
    newBr = document.createElement('br');
    newClearDiv = document.createElement('div');
    newClearDiv.className = 'clear';

    // Add the new elements to the DOM
    newContainerDiv.appendChild(newInput);
    newContainerDiv.appendChild(newBr);
    newContainerDiv.appendChild(newClearDiv);
    document.getElementById('uploads_container').appendChild(newContainerDiv);

  }

</script>

<!-- just create one input at first, so we don't need the PHP loop any more -->

<div id="uploads_container">
  <!-- we wrap it all in an outer container div with an id, to ease the task of adding more elements -->
  <div class="smWidth">
    <input type="file" name="upload_file_1" onchange="inputChange();" />
    <br />
    <div class="clear">
    </div>
  </div>
</div>
于 2011-09-06T21:57:21.467 回答
0

尝试将其他一些事件挂钩到您的文件字段。据我所知，jQuery 有一个非常有用的事件，叫做 .change()

我认为这适用于你的情况。

于 2011-09-06T21:31:55.330 回答