0

I am wondering if anyone has successfully generated an EC2 v2 signature for their API using php. All examples/libraries I can find online are for v1 of the signature and that has been deprecated due to insecurities. An existing library that implements the signature generation would be appreciated too.

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4 回答 4

1

http://mierendo.com/software/aws_signed_query/

我相信那是V2

于 2009-11-25T00:34:04.927 回答
0

Here's a PHP Library that supports V2. I haven't tried it though.

于 2009-04-08T00:04:56.030 回答
0

使用常量 AWSSECRET 来散列签名，而不是 $AWSKEY（未引用的变量）。

于 2012-05-13T07:28:53.407 回答
0

这是我编写并一直在使用的一些代码：

define("AWSKEY", "Your AWS Key");
define("AWSSECRET", "Your AWS Secret");
public function get($parameters, $host) {

    // Build out the variables
    $domain = "https://$host/";
    $parameters['AWSAccessKeyId'] = AWSKEY;
    $parameters['Timestamp'] = date('c');
    $parameters['Version'] = '2007-11-07';
    $parameters['SignatureMethod'] = 'HmacSHA256';
    $parameters['SignatureVersion'] = 2;

    // Write the signature
    $signature = "GET\n";
    $signature .= "$host\n";
    $signature .= "/\n";

    $sigparams = $parameters;

    ksort($sigparams);

    $first = true;
    foreach($sigparams as $key=>$param) {
        $signature .= (!$first ? '&' : '') . rawurlencode($key) . '=' . rawurlencode($param);
        $first = false;
    }
    $signature = hash_hmac('sha256', $signature, $AWSKEY, true);
    $signature = base64_encode($signature);
    $parameters['Signature'] = $signature;

    $url = $domain . '?';
    $first = true;
    foreach($parameters as $key=>$param) {
        $url .= (!$first ? '&' : '') . rawurlencode($key) . '=' . rawurlencode($param);
        $first = false;
    }

    $ch = curl_init(trim($url));
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

    $output = curl_exec($ch);

    return $output;

}

下面是你如何使用它：

$params = array(
    'Action' => 'ListDomains'
);
$db->get($params, 'sdb.amazonaws.com');

ListDomains这将在 SimpleDB 上执行查询。该函数本身将返回 Amazon 的输出。对于更复杂的命令（即：PUT、POST 等），不需要进行任何重大修改。

于 2009-11-25T00:25:09.743 回答