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我有一个简单的 restful 服务,它使用 RestEasy 将 JAXB 注释 bean 转换为响应 XML。XML 标记可能包含转义的特殊字符(例如 –)。但是 RestEasy marshaller 又一次逃脱了 & 符号,我得到 – 而不是 – 在结果 XML 中。

我应该如何避免不必要的&符号转义?

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我一直在寻找这个,我无法找到微调 RESTEasy 在写出响应时转义字符的方式。我正在使用拦截器来防止这种编码。

作为参考,它在对 UTF-8 XML 进行编码时发生在堆栈中的 setEscape() 处。

Encoded.setEscape(String, boolean) line: 107    
UTF8XmlOutput.doText(String, boolean) line: 315 
UTF8XmlOutput.text(String, boolean) line: 299   
XMLSerializer.leafElement(Name, String, String) line: 325   
RuntimeBuiltinLeafInfoImpl$1.writeLeafElement(XMLSerializer, Name, String, String) line: 210    
RuntimeBuiltinLeafInfoImpl$1.writeLeafElement(XMLSerializer, Name, Object, String) line: 209    
TransducedAccessor$CompositeTransducedAccessorImpl<BeanT,ValueT>.writeLeafElement(XMLSerializer, Name, BeanT, String) line: 250 
SingleElementLeafProperty<BeanT>.serializeBody(BeanT, XMLSerializer, Object) line: 98   
ClassBeanInfoImpl<BeanT>.serializeBody(BeanT, XMLSerializer) line: 332  
XMLSerializer.childAsXsiType(Object, String, JaxBeanInfo, boolean) line: 699    
SingleElementNodeProperty<BeanT,ValueT>.serializeBody(BeanT, XMLSerializer, Object) line: 152   
ClassBeanInfoImpl<BeanT>.serializeBody(BeanT, XMLSerializer) line: 332  
XMLSerializer.childAsSoleContent(Object, String) line: 593  
ClassBeanInfoImpl<BeanT>.serializeRoot(BeanT, XMLSerializer) line: 320  
XMLSerializer.childAsRoot(Object) line: 494 
MarshallerImpl.write(Object, XmlOutput, Runnable) line: 315 
MarshallerImpl.marshal(Object, Result) line: 244    
MarshallerImpl(AbstractMarshallerImpl).marshal(Object, OutputStream) line: 75   
JAXBXmlRootElementProvider(AbstractJAXBProvider<T>).writeTo(T, Class<?>, Type, Annotation[], 
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于 2012-03-15T19:16:38.563 回答