ruby - 如何在 Ruby 的较长字符串中匹配以 'H' 开头的 10 个字符的子字符串？

Question

我有以下字符串：

/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml

在 Ruby 中，如何提取以字母开头H并在H. 在上面的示例中，子字符串将是H200000787

Answer 1

String#[]方法是你需要的：

str = '/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml'

puts str[/H\d{9}/]     #=> H200000787

Answer 2

irb(main):001:0> s = "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
=> "/Users/patelc75/Documents/code/haloror/dialup/H200000787_1313406125/H200000787_1313389058_1.xml"
irb(main):002:0> s =~ /H\d{9}/
=> 46
irb(main):003:0> $&
=> "H200000787"