10

不使用 MSSQL、DB2 或 Oracle。没有 CTE。没有 OVERLAP 谓词。没有 INTERVAL 数据类型。情况:要修理的车辆在收到所有订购的零件后才能开始工作。在开始维修之前,可以多次订购零件。我们需要提取车辆处于“部件搁置”状态的时间

因此,对于标识为 id = 1 的车辆,在 4 个不同的场合订购 (d1) 和接收 (d2) 零件

    ID     d1     d2
     1     8/1    8/8
     1     8/2    8/6
     1     8/12   8/14
     1     8/3    8/10

 8/1                             8/8
  d1                              d2   
  |-------------------------------|  
         8/2             8/6                    8/12      8/14                  
         d1               d2                     d1        d2     
          |---------------|                      |----------|    
                   8/3                 8/10
                   d1                    d2
                   |---------------------|   
 8/1                                                       8/14
  |---------------------------------------------------------|  = 13 days
                                        8/10    8/12
  |--------------------------------------|    +  |----------|  = parts hold  = 11 days

从上面可以看出,开始工作的等待时间(假设 8 月 1 日为车辆可以工作的日期)为 13 天。等待零件的实际时间是 11 天,这是我们需要从数据中得出的数字。实际的日期时间数据将是时间戳,我们将从中提取小时数,我们在此示例数据中使用日期以简化演示。我们正在努力生成一个基于集合(不是 psm,不是 udf,不是光标)的解决方案。TIA

4

3 回答 3

6

我无法让@Alex W 的查询工作。它不是标准 SQL,因此需要大量重写才能与 SQL Server(我可以测试)兼容。但它确实给了我一些灵感,我对此进行了扩展。


找出每个不间断等待周期的所有起点:

SELECT DISTINCT
    t1.ID,
    t1.d1 AS date,
    -DATEDIFF(DAY, (SELECT MIN(d1) FROM Orders), t1.d1) AS n
FROM Orders t1
LEFT JOIN Orders t2                   -- Join for any events occurring while this
    ON t2.ID = t1.ID                  -- is starting. If this is a start point,
    AND t2.d1 <> t1.d1                -- it won't match anything, which is what
    AND t1.d1 BETWEEN t2.d1 AND t2.d2 -- we want.
GROUP BY t1.ID, t1.d1, t1.d2
HAVING COUNT(t2.ID) = 0

和端点的等价物:

SELECT DISTINCT
    t1.ID,
    t1.d2 AS date,
    DATEDIFF(DAY, (SELECT MIN(d1) FROM Orders), t1.d2) AS n
FROM Orders t1
LEFT JOIN Orders t2
    ON t2.ID = t1.ID
    AND t2.d2 <> t1.d2
    AND t1.d2 BETWEEN t2.d1 AND t2.d2
GROUP BY t1.ID, t1.d1, t1.d2
HAVING COUNT(t2.ID) = 0

n是自某个共同时间点以来的天数。起点为负值,终点为正值。这样我们就可以将它们相加以获得两者之间的天数。

span = end - start
span = end + (-start)
span1 + span2 = end1 + (-start1) + end2 + (-start2)

最后,我们只需要添加一些东西:

SELECT ID, SUM(n) AS hold_days
FROM (
   SELECT DISTINCT
       t1.id,
       t1.d1 AS date,
       -DATEDIFF(DAY, (SELECT MIN(d1) FROM Orders), t1.d1)  AS n
   FROM Orders t1
   LEFT JOIN Orders t2
      ON t2.ID = t1.ID
      AND t2.d1 <> t1.d1
      AND t1.d1 BETWEEN t2.d1 AND t2.d2
   GROUP BY t1.ID, t1.d1, t1.d2
   HAVING COUNT(t2.ID) = 0
   UNION ALL
   SELECT DISTINCT
       t1.id,
       t1.d2 AS date,
       DATEDIFF(DAY, (SELECT MIN(d1) FROM Orders), t1.d2) AS n
   FROM Orders t1
   LEFT JOIN Orders t2
      ON t2.ID = t1.ID
      AND t2.d2 <> t1.d2
      AND t1.d2 BETWEEN t2.d1 AND t2.d2
   GROUP BY t1.ID, t1.d1, t1.d2
   HAVING COUNT(t2.ID) = 0
   ORDER BY ID, date
) s
GROUP BY ID;

输入表(订单):

ID   d1           d2
 1   2011-08-01   2011-08-08
 1   2011-08-02   2011-08-06
 1   2011-08-03   2011-08-10
 1   2011-08-12   2011-08-14
 2   2011-08-01   2011-08-03
 2   2011-08-02   2011-08-06
 2   2011-08-05   2011-08-09

输出:

ID   hold_days
 1          11
 2           8

或者,您可以使用存储过程来执行此操作。

CREATE PROCEDURE CalculateHoldTimes
    @ID int = 0
AS
BEGIN
    DECLARE Events CURSOR FOR
    SELECT *
    FROM (
        SELECT d1 AS date, 1 AS diff
        FROM Orders
        WHERE ID = @ID
        UNION ALL
        SELECT d2 AS date, -1 AS diff
        FROM Orders
        WHERE ID = @ID
    ) s
    ORDER BY date;

    DECLARE @Events_date date,
            @Events_diff int,
            @Period_start date,
            @Period_accum int,
            @Total_start date,
            @Total_count int;

    OPEN Events;

    FETCH NEXT FROM Events
    INTO @Events_date, @Events_diff;

    SET @Period_start = @Events_date;
    SET @Period_accum = 0;
    SET @Total_start = @Events_date;
    SET @Total_count = 0;

    WHILE @@FETCH_STATUS = 0
    BEGIN
        SET @Period_accum = @Period_accum + @Events_diff;

        IF @Period_accum = 1 AND @Events_diff = 1
            -- Start of period
            SET @Period_start = @Events_date;
        ELSE IF @Period_accum = 0 AND @Events_diff = -1
            -- End of period
            SET @Total_count = @Total_count +
                DATEDIFF(day, @Period_start, @Events_date);

        FETCH NEXT FROM Events
        INTO @Events_date, @Events_diff;
    END;

    SELECT
        @Total_start AS d1,
        @Events_date AS d2,
        @Total_count AS hold_time;
END;

调用它:

EXEC CalculateHoldTimes 1;
于 2011-08-29T06:28:40.953 回答
5

这条 SQL 语句似乎得到了你想要的(t 是 sampe 表的表名):

SELECT
   d.id, 
   d.duration, 
   d.duration - 
   IFNULL(
      ( SELECT Sum( timestampdiff( SQL_TSI_DAY, 
                                   no_hold.d2, 
                                   ( SELECT min(d1) FROM t t4 
                                     WHERE t4.id = no_hold.id and t4.d1 > no_hold.d2 )))
        FROM ( SELECT DISTINCT id, d2 FROM t t1 
               WHERE ( SELECT sum( IIF( t1.d2 between t2.d1 and t2.d2, 1, 0 ) ) 
                       FROM t t2 WHERE t2.id = t1.id and t2.d2 <> t1.d2 ) = 0 
             And d2 <> ( select max( d2 ) from t t3 where t3.id = t1.id )) no_hold
        WHERE no_hold.id = d.id ),
      0 ) "parts hold"
FROM 
   ( SELECT id, timestampdiff( SQL_TSI_DAY, min( d1 ), max( d2 ) ) duration
     FROM t GROUP BY id ) d

外部查询获取修复工作的持续时间。复杂子查询计算不等待零件的总天数。这是通过定位车辆不等待零件的开始日期来完成的,然后计算直到它再次开始等待零件的天数:

// 1) The query for finding the starting dates when the vehicle is not waiting for parts, 
// i.e. finding all d2 that is not within any date range where the vehicle is waiting for part.
// The DISTINCT is needed to removed duplicate starting "no hold" period.

SELECT DISTINCT id, d2 
FROM t t1
WHERE ( SELECT sum( IIF( t1.d2 between t2.d1 and t2.d2, 1, 0 ) ) from t t2 
        WHERE t2.id = t1.id and t2.d2 <> t1.d2 ) = 0 AND 
      d2 <> ( SELECT max( d2 ) FROM t t3 WHERE t3.id = t1.id ) )

// 2) 车辆不等待零件的天数是从上述查询到车辆 // 再次等待零件的日期

timestampdiff( SQL_TSI_DAY, no_hold.d2, ( SELECT min(d1) FROM t t4 WHERE t4.id = no_hold.id and t4.d1 > no_hold.d2 ) )

结合上述两个并汇总所有这些时间段,得出车辆不等待零件的天数。最后的查询添加了一个额外的条件来计算来自外部查询的每个 id 的结果。

这在具有许多 id 的非常大的表上可能不是非常有效。如果 id 仅限于一个或几个,应该没问题。

于 2011-08-30T21:33:25.620 回答
0
USE [DnnMasterShoraSystem]
GO
/****** Object:  StoredProcedure [dbo].[CalculateHoldTimes]    Script Date: 12/8/2014 1:36:12 PM ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

ALTER PROCEDURE [dbo].[CalculateHoldTimes]
    @PID int    
AS
BEGIN      
CREATE TABLE #tblTemp(
    [ID] [int] NOT NULL,
    [PID] [int] NOT NULL,
    [BID] [int] NOT NULL,
    [Active] [bit] NULL,
    [WorkStartDate] [nvarchar](10) NULL,
    [WorkEndDate] [nvarchar](10) NULL,
    [jobStateID] [int] NULL,
    [RegisterType] [int] NULL,
    [RegisterState] [int] NULL,
    [En_time] [datetime] NULL,
    [Fa_time] [nvarchar](40) NULL,
    [Status] [nvarchar](100) NULL,
    [PortalId] [int] NULL,
    [ModuleId] [int] NULL,
    [UserId] [int] NULL,
    [BrName] [nvarchar](150) NULL,
    [BrCode] [nvarchar](20) NULL,
    [WorkEndDate_New] [nvarchar](10) NULL
) ON [PRIMARY]

insert into #tblTemp
select * from [dbo].[Shora.Personel_Branch_Copy] 
        where WorkStartDate is not null 
        --and [dbo].[ShamsiToMiladi](WorkStartDate) <GETDATE() 
        --and [dbo].[ShamsiToMiladi](WorkEndDate) <GETDATE() 
        and PID=@PID
        --and [dbo].[ShamsiToMiladi](WorkEndDate)<[dbo].[ShamsiToMiladi](@NewDate)
        order by WorkStartDate

DECLARE Events CURSOR FOR
    SELECT [dbo].[ShamsiToMiladi](WorkStartDate) AS StartDate,[dbo].[ShamsiToMiladi](WorkEndDate) AS EndDate
        FROM #tblTemp        
    ORDER BY StartDate;

--drop table #tblTemp

    DECLARE @SDate date,
            @EDate date,
            @Period_Start date,
            @Period_End date,
            @Total int,
            @OldSDate date,
            @OldEDate date


    OPEN Events;

    FETCH NEXT FROM Events
    INTO @SDate, @EDate;

    set @Total=0
    SET @Period_Start =@SDate
    set @Period_End=@EDate

    WHILE @@FETCH_STATUS = 0
    BEGIN      
    if @OldSDate>@Period_End
        begin
            set @Period_Start=@SDate            

            if @Period_End>=@Period_Start
            set @Total+=DATEDIFF(DAY,@Period_Start,@Period_End)
        end
    else if @SDate<@Period_End
        begin       
        set @Period_Start=@Period_Start     
            set @Total=DATEDIFF(DAY,@Period_Start,@Period_End)
        end

        set @OldSDate=@SDate 
        set @OldEDate=@EDate

        FETCH NEXT FROM Events
        INTO @SDate, @EDate;

        if  @Period_End<@EDate
        set @Period_End=@EDate

    END;

INSERT INTO [dbo].[PersonelDays]
           (PID
           ,[Total_Start]
           ,[Total_End]
           ,[Total_count])
     VALUES
           (@PID,           
            @Period_Start,
            @Period_End,
            @Total
           )

drop table #tblTemp
CLOSE Events
DEALLOCATE Events
END;
于 2014-12-08T10:04:18.007 回答