15

我正在尝试使用 HQL（休眠查询语言）在两个表之间创建联合。此 SQL 脚本在我的 SQL 服务器上运行良好：

SELECT COUNT(DISTINCT linkedin_id) as test, school_name
FROM
(SELECT * FROM alum_education 
 UNION
 SELECT * FROM alum_connection_educations) AS UNIONS where school_name='some string'

问题是，当我尝试像这样在 grails 中运行它时：

     def countOfEdu = AlumEducation.executeQuery("select count (distinct linkedinId ) as countOfEdu, schoolName as SchoolName from (SELECT * FROM alumEducation UNION SELECT * FROM alumConnectionEducations) AS UNIONS where schoolName='some string'" )

我收到此错误：

  org.hibernate.hql.ast.QuerySyntaxException: unexpected token: ( near line 1, column 83 [select count(distinct linkedinId )  as countOfEdu, schoolName as SchoolName  from (SELECT * FROM alumEducation UNION SELECT * FROM alumConnectionEducations) AS UNIONS where schoolName='Duquesne University']

如何在 grails 中运行上述 SQL 语句？

谢谢杰森

4

3 回答 3

40

HQL 不支持联合。自 2005 年以来，Hibernate 的 JIRA 中存在一个问题。

于 2011-08-24T21:30:11.177 回答
1

我想分享一种我发现的避免这种情况的方法。这里唯一的规则是具有相同的类型，在这种情况下是一个字符串，对应于返回列表的类型，您可以添加任意数量的表：

public List<String> findByCPForCNPJ(String query){
TypedQuery<String> ccpf = manager.createQuery("select cpf from PessoaFisica where cpf like :pCpf", String.class);
ccpf.setParameter("pCpf", "%" + query + "%");
List<String> lista1 = ccpf.getResultList();

TypedQuery<String> ccnpj = manager.createQuery("select cnpj from PessoaJuridica where cnpj like :pCnpj", String.class);
ccnpj.setParameter("pCnpj", "%" + query + "%");

lista1.addAll(ccnpj.getResultList());
return lista1;
}

我在 JAVA 中使用了一种方法来解决这个问题。我希望我贡献了一点，祝大家好运......

于 2014-12-19T16:09:05.077 回答
0

在您的情况下，真正的问题是 EJBQL 的 FROM 子句不支持子查询。

于 2014-10-28T19:04:53.930 回答