8

当我收到 Web 异常时，我很难从 vb.net 中的 HTTP Web 请求中获取响应文本。

这是我正在使用的代码。

Try
            myWebResponse = CType(request.GetResponse(), HttpWebResponse)
            myStreamReader = New StreamReader(myWebResponse.GetResponseStream())

            ResponseText = myStreamReader.ReadToEnd
            If myWebResponse.StatusCode = HttpStatusCode.Accepted Or myWebResponse.StatusCode = 200 Then
                SendResult = True 'Sent 
                SendStatus = 1 'message sent successfully
                Try
                    Integer.TryParse(myWebResponse.Headers("Number-Of-MT-PDU"), num_MT_PDU)
                Catch ex As Exception
                End Try
            Else
                SendStatus = 2 'message processed but not sent successfully
            End If
        Catch e As WebException
            If (e.Status = WebExceptionStatus.ProtocolError) Then
                Dim response As WebResponse = e.Response
                Using (response)
                    Dim httpResponse As HttpWebResponse = CType(response, HttpWebResponse)
                    statusCode = httpResponse.StatusCode
                    Try
                        myStreamReader = New StreamReader(response.GetResponseStream())
                        Using (myStreamReader)
                            ResponseText = myStreamReader.ReadToEnd & "Status Description = " & HttpWebResponse.StatusDescription
                        End Using
                    Catch ex As Exception
                        Logger.LogError(Me, ex)
                    End Try
                End Using

烦人的是，我联系的 API 使用 404 作为有效响应。如果我将请求放在浏览器中，将显示一些消息文本。我希望能够在我的程序中使用该文本。我不能简单地使用错误代码来确定操作，因为我认为我无法区分有效的 404 响应和实际错误。

在代码中这一行

myWebResponse = CType(request.GetResponse(), HttpWebResponse)

抛出异常。

在异常中，我可以获得 404 代码和描述，但不能获得响应流。它始终为空。

如果我得到 200 响应，我会在响应流中得到文本没有问题。

在 Web 异常响应对象（在 Visual Studios 调试器中）中，我检查了标头和对象值，但在任何地方都找不到响应文本。如果我将请求 URL 粘贴在浏览器中，我会返回响应文本，即使它是 404。

提琴手的原始响应：

HTTP/1.1 404 Not Found Connection: close Content-Type: text/plain; charset=UTF-8 Content-Length: 35 "The response Message"

关于如何在我的程序中获得“响应消息”的任何想法？我必须在服务器上使用 .Net。

感谢任何人都可以提供的任何帮助。

4

2 回答 2

4

此 LINQPad 查询工作正常，转储我的 Web 服务器的“未找到”错误网页提供的 HTML：

Dim rq = System.Net.WebRequest.Create(New Uri("http://localhost/test"))
Try 
  Dim rs = rq.GetResponse
  rs.Dump
Catch Ex As System.Net.WebException
 Dim rs = Ex.Response
 Call (New StreamReader(rs.GetResponseStream)).ReadToEnd.Dump
End Try

仅供参考，您的代码对我有用，除了假定的拼写错误HttpWebResponse.StatusDescription（并注释掉“不相关的东西”），再次作为 LINQPad 查询（在 .NET 4.0 中）：

Dim request = WebRequest.Create("http://localhost/test")
Dim myStreamReader As StreamReader
Dim SendStatus As Integer = -1
Dim statusCode As HttpStatusCode
Dim ResponseText As String
Try
    Dim myWebResponse = CType(request.GetResponse(), HttpWebResponse)
        myStreamReader = New StreamReader(myWebResponse.GetResponseStream())

        ResponseText = myStreamReader.ReadToEnd
        If myWebResponse.StatusCode = HttpStatusCode.Accepted Or myWebResponse.StatusCode = 200 Then
            'SendResult = True 'Sent 
            SendStatus = 1 'message sent successfully
            'Try
            '    Integer.TryParse(myWebResponse.Headers("Number-Of-MT-PDU"), num_MT_PDU)
            'Catch ex As Exception
            'End Try
        Else
            SendStatus = 2 'message processed but not sent successfully
        End If
    Catch e As WebException
        If (e.Status = WebExceptionStatus.ProtocolError) Then
            Dim response As WebResponse = e.Response
            Using (response)
                Dim httpResponse As HttpWebResponse = CType(response, HttpWebResponse)
                statusCode = httpResponse.StatusCode
                Try
                    myStreamReader = New StreamReader(response.GetResponseStream())
                    Using (myStreamReader)
                        ResponseText = myStreamReader.ReadToEnd & "Status Description = " & httpResponse.StatusDescription ' HttpWebResponse.StatusDescription
                    End Using
                Catch ex As Exception
                    'Logger.LogError(Me, ex)
                    ex.Dump("Exception")
                End Try
            End Using
      End If
End Try
ResponseText.Dump("ResponseText")

我还确认了上述代码（添加了推断As子句并将.Dump调用转换为Console.WriteLine）在 .NET 2.0 和 VB8 中有效。

于 2012-11-03T13:22:53.230 回答
0

请注意，关键是即使 GetResponseStream() 的行为引发了 .NET WebException，HttpWebResponse 实际上是传递给 WebException 对象，因此在 Catch 中时，您对 WebException.Response 对象执行新的 GetResponseStream()。

下面，在初始 GetResponseStream() 的 Catch 中的代码非常相似

   Try 
            OriginalResponseStream = GetResponseStream(OriginalHTTPWebResponse)

   Catch wex as WebException
            Dim response As WebResponse = wex.Response
            Dim statusCode As HttpStatusCode
            Dim ResponseText As String

            Dim httpResponse As HttpWebResponse = CType(response, HttpWebResponse)
            statusCode = httpResponse.StatusCode

            Try

                Dim myStreamReader As New StreamReader(response.GetResponseStream())
                Using (myStreamReader)
                    ResponseText = myStreamReader.ReadToEnd
                    Process(ResponseText) '<===as in whatever you need to do with the response
                End Using
            Catch ex As Exception

                HandleIt(ex.Message) '<===as in whatever you want to do if Exception during the above

            End Try

   End Try
于 2014-03-13T15:18:22.250 回答