1

我不确定为什么这无法解开符号：

#include <cxxabi.h>
void _debugBacktrace(code_part part)
{
#if defined(WZ_OS_LINUX) && defined(__GLIBC__)
    void *btv[20];
    unsigned num = backtrace(btv, sizeof(btv) / sizeof(*btv));
    char **btc = backtrace_symbols(btv, num);
    unsigned i;
    char buffer[255];
    for (i = 1; i + 2 < num; ++i) 
    {
        int status = -1;
        size_t demangledLen = 0;
        memset(buffer, 0, 255);
        char *readableName = abi::__cxa_demangle(btc[i], buffer, &demangledLen, &status);
        if (status == 0)
        {
            _debug(0, part, "BT", "%s", readableName);
        }
        else
        {
            _debug(0, part, "BT", "%s [status: %i]", btc[i], status);
        }
        
    }
    free(btc);
#else
    // debugBacktrace not implemented.
#endif
}

标准输出：

error   |02:25:21: [BT:0] ./src/warzone2100(_ZNK5EcKey4signEPKvm+0x98) [0x16405da] [status: -2]
error   |02:25:21: [BT:0] ./src/warzone2100(_Z8recvPing8NETQUEUE+0x1ab) [0x126bc2d] [status: -2]
error   |02:25:21: [BT:0] ./src/warzone2100(_ZN27WzMultiplayerOptionsTitleUI21frontendMultiMessagesEb+0x7d9) [0x11ce219] [status: -2]
error   |02:25:21: [BT:0] ./src/warzone2100(_ZN27WzMultiplayerOptionsTitleUI3runEv+0x45) [0x11cf32b] [status: -2]
error   |02:25:21: [BT:0] ./src/warzone2100(_Z9titleLoopv+0x1aa) [0x1480b35] [status: -2]
error   |02:25:21: [BT:0] ./src/warzone2100() [0x1169cbc] [status: -2]
...
...
### BUT this works?
> addr2line -f 0x16405da -C  -e ./src/warzone2100 
EcKey::sign(void const*, unsigned long) const
/home/docker/code/lib/framework/crc.cpp:284

在 docker 下编译（C++11）：

docker@b12fbaed9c6c:~/code> g++ --version
g++ (SUSE Linux) 11.2.1 20210816 [revision 056e324ce46a7924b5cf10f61010cf9dd2ca10e9]
docker@b12fbaed9c6c:~/code> ld --version
GNU ld (GNU Binutils; openSUSE Tumbleweed) 2.37.20210803-1

在主机上执行：

> g++ --version
g++ (SUSE Linux) 11.2.1 20220103 [revision d4a1d3c4b377f1d4acb34fe1b55b5088a3f293f6]

> ld -version
GNU ld (GNU Binutils; openSUSE Tumbleweed) 2.37.20211112-3
4

1 回答 1

0

一方面，您没有__cxa_demangle正确调用。文档说：

output_buffer
使用 malloc 分配的*length字节内存区域，其中存储了解构后的名称。如果output_buffer不够长，则使用realloc. output_buffer可能是NULL; 在这种情况下，解构后的名称被放置在分配有malloc.

您正在传递一个堆栈 buffer。摆脱它（和无意义的memset），而是这样做：

    for (i = 1; i + 2 < num; ++i) 
    {
        int status = -1;
        char *readableName = abi::__cxa_demangle(btc[i], NULL, NULL, &status);
        if (status == 0)
        {
            _debug(0, part, "BT", "%s", readableName);
        }
        else
        {
            _debug(0, part, "BT", "%s [status: %i]", btc[i], status);
        }
        free(readableName);
    }

更新：

第二个问题是您似乎期望__cxa_demangle()忽略不属于损坏名称的任何字符，并破坏其余部分。（您没有显示实际内容btc[i]是什么，但从输出中它似乎包含类似 的字符串./src/warzone2100(_ZNK5EcKey4signEPKvm+0x98) [0x16405da]）。

如以下测试所示，__cxa_demangle()不忽略任何内容；它需要错位名称，而不是“包含错位名称的东西”。

#include <cxxabi.h>
#include <string.h>

#include <array>
#include <iostream>

int main()
{
  const std::array<const char *, 5> bt = {
    "./src/warzone2100(_ZNK5EcKey4signEPKvm+0x98) [0x16405da]",
    "./src/warzone2100(_Z8recvPing8NETQUEUE+0x1ab) [0x126bc2d]",
    "./src/warzone2100(_ZN27WzMultiplayerOptionsTitleUI21frontendMultiMessagesEb+0x7d9) [0x11ce219]",
    "./src/warzone2100(_ZN27WzMultiplayerOptionsTitleUI3runEv+0x45) [0x11cf32b]",
    "./src/warzone2100(_Z9titleLoopv+0x1aa) [0x1480b35]",
  };
  std::cout << "Wrong way:" << std::endl << std::endl;
  for (const char* p : bt) {
    int status;
    char *demangled =  abi::__cxa_demangle(p, NULL, NULL, &status);
    std::cout << p << " " << status << std::endl;
    free(demangled);
  }

  auto trim = [](const char *in, char *out) {
    const char *begin = strchr(in, '_');
    const char *end = strchr(begin, '+');
    memcpy(out, begin, end - begin);
    out[end - begin] = '\0';
  };

  std::cout << std::endl << "Right way:" << std::endl << std::endl;
  for (const char* p : bt) {
    int status;
    char buf[1024];

    trim(p, buf);
    char *demangled =  abi::__cxa_demangle(buf, NULL, NULL, &status);
    std::cout << buf << " -> " << demangled << " " << status << std::endl;
    free(demangled);
  }
}

使用(Debian 11.2.0-14)，我得到：

g++ -g foo.cc && ./a.out
Wrong way:

./src/warzone2100(_ZNK5EcKey4signEPKvm+0x98) [0x16405da] -2
./src/warzone2100(_Z8recvPing8NETQUEUE+0x1ab) [0x126bc2d] -2
./src/warzone2100(_ZN27WzMultiplayerOptionsTitleUI21frontendMultiMessagesEb+0x7d9) [0x11ce219] -2
./src/warzone2100(_ZN27WzMultiplayerOptionsTitleUI3runEv+0x45) [0x11cf32b] -2
./src/warzone2100(_Z9titleLoopv+0x1aa) [0x1480b35] -2

Right way:

_ZNK5EcKey4signEPKvm -> EcKey::sign(void const*, unsigned long) const 0
_Z8recvPing8NETQUEUE -> recvPing(NETQUEUE) 0
_ZN27WzMultiplayerOptionsTitleUI21frontendMultiMessagesEb -> WzMultiplayerOptionsTitleUI::frontendMultiMessages(bool) 0
_ZN27WzMultiplayerOptionsTitleUI3runEv -> WzMultiplayerOptionsTitleUI::run() 0
_Z9titleLoopv -> titleLoop() 0
于 2022-03-05T04:00:46.073 回答