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我想使用 CosmosDB 容器中的数据创建一个 API 端点。数据结构如下：

{
    "id": "28.02.2022 09:31:42",
    "time": 1646037099,
    "states": [
        [
            "aa56db",
            "UAL339  ",
            "United States",
            1646037098,
            1646037099,
            -84.9531,
            25.9777,
            11277.6,
            false,
            239.52,
            25.85,
            0,
            null,
            11811,
            null,
            false,
            0,
            4
        ],
        [
            "3c403f",
            "FME     ",
            "Germany",
            1646037012,
            1646037012,
            13.5172,
            52.3712,
            null,
            true,
            5.14,
            247.5,
            null,
            null,
            null,
            null,
            false,
            0,
            17
        ],

首先，我创建了如下所示的模型“OpenSky”：

public class OpenSky
    {
        [JsonProperty("id")]
        public string Id { get; set; }

        [JsonProperty("time")]
        public decimal? Time { get; set; }

        [JsonProperty("states")]
        public List<List<**OpenSkyFlight**>> States { get; set; }
       
    }

属性状态是对象类型OpenSkyFlight的列表列表。OpenSkyFlight 模型如下所示：

public class OpenSkyFlight
    {                
        public string Icao24 { get; set; }

        public string Callsign { get; set; }

        public string OriginCountry { get; set; }

        public int? TimePosition { get; set; }

        public int? LastContact { get; set; }

        public float? Longitude { get; set; }

        public float? Latitude { get; set; }

        public float? BaroAltitude { get; set; }

        public bool? OnGround { get; set; }

        public float? Velocity { get; set; }

        public float? TrueTrack { get; set; }

        public float? VerticalRate { get; set; }

        public string Sensors { get; set; }

        public float? GeoAltitude { get; set; }

        public string Squawk { get; set; }

        public bool? Spi { get; set; }

        public int? PositionSource { get; set; }
    }

问题是我不知道如何将这些 json 属性“状态”扁平化为像 OpenSkyFlight 这样的对象类型。我在 Context.cs 中尝试了以下内容：

// OpenSky
            modelBuilder.Entity<OpenSky>()
                .Property(p => p.Id)
                .ToJsonProperty("id");

            modelBuilder.Entity<OpenSky>()
                .Property(p => p.Time)
                .ToJsonProperty("time");
           

            modelBuilder.Entity<OpenSky>()
                .Property(p => p.States)
                .HasConversion(
                    v => JsonConvert.SerializeObject(v),
                    v => JsonConvert.DeserializeObject<List<List<object>>>(v => new Icao24 = JsonConvert.ToString(v[0]))
                )
                .ToJsonProperty("states");

先感谢您！

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