1 
Select ID,LISTAGG(CATEGORY_CD, ',') WITHIN GROUP(ORDER BY CAST(P_NO as INT)) AS CATEGORY_CD
FROM table1
WHERE DATE = '2022-02-02'
AND CATEGORY_FLAG = '0'
AND CAT_SRC_CD NOT IN ('0','1','2','3')
group by ID

我需要重写上面的查询，这样它应该是 ORDERED BY P_NO 并且我需要为 CATEGORY_CD 列显示不同的值。

我尝试了下面提到的逻辑，并在子查询中使用了 ORDER BY P_NO。不知道我写的逻辑是否正确。

SELECT ID,LISTAGG(distinct CATEGORY_CD, ',') WITHIN GROUP(ORDER BY CAST(CATEGORY_CD as INT)) AS CATEGORY_CD
 FROM 
      (SELECT distinct ID,CREATE_DT,CATEGORY_CD, 
          TRY_CAST(P_NO as INTEGER) as P_NO
        FROM table1 
        WHERE DATE = '2022-02-02'
        AND CATEGORY_FLAG = '0'
        AND CAT_SRC_CD NOT IN ('0','1','2','3')
        ORDER BY P_NO
      ) 
    GROUP BY 
      ID;

我提到的原始查询给出了以下结果。我应该只显示 CATEGORY_CD 列的不同值，结果应该是 ORDERED BY P_NO 列。

      ID                CATEGORY_CD
      
      169174408          5,5,5,5
      169174408          2,1,1
      169174408          12,12,12,12,12,12
      839946105          2,2,2,2,3,3,3,3,3,3,3,3

请指导我实施正确的逻辑。提前致谢 ：）

另外，如果我需要在原始查询中添加另外几列，请指导我。我再次添加了我的原始 SQL 查询，添加了另一列。

Select ID,LISTAGG(CATEGORY_CD, ',') WITHIN GROUP(ORDER BY CAST(P_NO as INT)) AS CATEGORY_CD,
LISTAGG(CATEGORY_DTL, ',') WITHIN GROUP(ORDER BY CAST(P_NO as INT)) AS CATEGORY_DTL
FROM table1
WHERE DATE = '2022-02-02'
AND CATEGORY_FLAG = '0'
AND CAT_SRC_CD NOT IN ('0','1','2','3')
group by ID
4

1 回答 1

1

用于QUALIFY选择不同的CATEGORY_CDper ID：

WITH cte AS (
    SELECT *
    FROM table1
    WHERE DATE = '2022-02-02'
      AND CATEGORY_FLAG = '0'
      AND CAT_SRC_CD NOT IN ('0','1','2','3')
    QUALIFY ROW_NUMBER() OVER(PARTITION BY ID,CATEGORY_CD ORDER BY P_NO::INT) = 1
)
SELECT ID,LISTAGG(CATEGORY_CD, ',') WITHIN GROUP(ORDER BY P_NO::int) AS CATEGORY_CD
FROM cte
GROUP BY ID;
于 2022-02-27T18:45:33.617 回答