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我正在使用 playwright 来运行 UI 测试。这个测试请求获取一个URL，登录，然后检查页面内容。作为开始，我只是尝试登录并捕获

import keyring

import asyncio
from playwright.async_api import async_playwright,Page, expect
from utils.util import get_logger
logger = get_logger(__name__)



async def login_to_dashboard():
    
    url = r"https://mytesturl"
    credential = keyring.get_credential("webpage", None)
    username = credential.username
    password = credential.password

    async with async_playwright() as playwright:
        browser = await playwright.chromium.launch(channel="chrome",headless=False)
        context = await browser.new_context()
        page = await context.new_page()
        await page.goto(url)
        await page.locator("[placeholder=\"Username\"]").fill(username)
        await page.locator("[placeholder=\"Password\"]").fill(password)
        await page.locator("input:has-text(\"Sign In\")").click()
        html1 = await page.content()
        await page.screenshot(path="o.png")

        #logger.info(html1)
        url = page.url
        logger.info(url)
        
        
        await context.storage_state(path='login_data.json')


if __name__ == "__main__":
    asyncio.run(login_to_dashboard())

我从 python 命令行运行它。我可以看到 chrome 启动，填写了 id/password，然后 chrome 页面立即消失了。我page.screenshot(path="o.png")捕获了屏幕截图，但这是登录前的屏幕截图，而我的期望是它应该在我登录后捕获屏幕截图await page.locator("input:has-text(\"Sign In\")").click()。

如果我在这里误解了什么，你能告诉我吗？

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