-1

SwiftUI 状态属性应声明为 private。这对于封装它们的值以包含视图很有用,但会阻止预览使用默认初始化程序设置非默认状态。例如,这不会编译:

struct TemperatureView: View {
    @State private var isHot = false
    
    var body: some View {
        Text(isHot ? "Hot" : "Cold")
    }
}

struct TemperatureView_Previews: PreviewProvider {
    static var previews: some View {
        Group {
            TemperatureView(isHot: true)
            TemperatureView(isHot: false)
        }
    }
}

替换privatefileprivate同样的错误。如何预览私人视图状态?

4

1 回答 1

2

因为它是@State你可能想要做的:

init() {}

fileprivate init(isHot: Bool) {
    self._isHot = State(initialValue: isHot)
}
于 2022-02-19T18:37:24.327 回答