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我正在为我的flutter-web应用程序开发integration_test ....我遇到的tester.enterText()方法不输入整数，双值，因为它的数据类型仅限于字符串类型。如果我TextField只接受数字和keyboardType属性设置为keyboardType: TextInputType.number怎么办？

尝试将其类型转换为 String 类型，但结果TextField不会接受任何非字符串值。下面的测试用例失败，但有以下异常：期望值类型String，但得到类型之一int

可重复的样品：

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';

void main() {
  runApp(const MyApp());
}

class MyApp extends StatelessWidget {
  const MyApp({Key? key}) : super(key: key);

  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      title: 'Flutter Demo',
      theme: ThemeData(
        primarySwatch: Colors.blue,
      ),
      home: const MyHomePage(title: 'Flutter Demo Home Page'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  const MyHomePage({Key? key, required this.title}) : super(key: key);

  final String title;

  @override
  State<MyHomePage> createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
  final _scaleTextController = TextEditingController();
  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: Text(widget.title),
      ),
      body: Container(
        alignment: Alignment.center,
        child: TextFormField(
          controller: _scaleTextController,
          inputFormatters: [
            FilteringTextInputFormatter.allow(
              RegExp(r'^\d*\.?\d{0,6}'),
            ),
          ],
          keyboardType: TextInputType.number,
          autofocus: true,
        ),
      ),
      floatingActionButton: FloatingActionButton(
        onPressed: () {},
        tooltip: 'Increment',
        child: const Icon(Icons.add),
      ),
    );
  }
}

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:flutter_test/flutter_test.dart';
import 'package:integration_test/integration_test.dart';
import 'package:hello_world/main.dart' as app;

void main() async {
  group('Complete E2E Test', () {
    IntegrationTestWidgetsFlutterBinding.ensureInitialized();

    setUp(() {
      app.main();
    });

    testWidgets('Hello World test', (WidgetTester tester) async {
      final inputField = find.byType(TextField).first;
      await tester.tap(inputField);
      await tester.enterText(inputField, 2 as String);
    });
  });
}
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1 回答 1

0

只需使用toString()而不是强制转换

如

假设你有一个 int 变量

int x = 2;

要将其更改为字符串，只需使用

x.toString();
于 2022-02-17T08:35:19.837 回答