6

我已经为此工作了一段时间。我想知道如何获得这张桌子：

id       open_dt             ops_hrs
1        10/31/2011          7:00AM - 5:30PM
2        11/1/2011           7:00AM - 5:00PM
3        11/2/2011           7:00AM - 5:00PM
4        11/3/2011           7:00AM - 5:00PM
5        11/6/2011           7:00AM - 7:00PM
6        11/8/2011           7:00AM - 5:00PM

看起来像这张表：

max_date          min_date     ops_hrs
10/31/2011        10/31/2011   7:00AM - 5:30PM
11/1/2011         11/3/2011    7:00AM - 5:00PM
11/6/2011         11/6/2011    7:00AM - 7:00PM
11/8/2011         11/8/2011    7:00AM - 5:00PM

我尝试使用游标，但没有必要。此外，它必须被分组。只要连续几天休息，就会发生新的分组。任何帮助，将不胜感激。

此查询将生成上述示例数据

;
WITH pdog (id, open_dt,ops_hrs) AS
(
SELECT 1, CAST('10/31/2011' AS datetime),  '7:00AM - 5:30PM'
UNION ALL SELECT 2, CAST('11/1/2011' AS datetime),'7:00AM - 5:00PM'
UNION ALL SELECT 3, CAST('11/2/2011' AS datetime),'7:00AM - 5:00PM'
UNION ALL SELECT 4, CAST('11/3/2011' AS datetime),'7:00AM - 5:00PM'
UNION ALL SELECT 5, CAST('11/6/2011' AS datetime),'7:00AM - 7:00PM'
UNION ALL SELECT 6, CAST('11/8/2011' AS datetime),'7:00AM - 5:00PM'
)
SELECT * FROM pdog
4

2 回答 2

5 
;WITH    CTE
          AS ( SELECT   * ,
                        DATEDIFF(DAY, 0, open_dt) -  ROW_NUMBER() OVER 
                              ( PARTITION BY ops_hrs ORDER BY open_dt ) AS Grp
               FROM     @x
             )
    SELECT  
            MIN(open_dt) AS min_date ,
            MAX(open_dt) AS max_date ,
            ops_hrs
    FROM    CTE
    GROUP BY ops_hrs ,
            Grp
    ORDER BY min_date
于 2011-08-17T22:20:37.890 回答
2

绝对比@Martin 的解决方案更复杂的逻辑，但我至少应该得到一点，因为他使用了我的@x 表——所以他的解决方案看起来更整洁。:-)

DECLARE @x TABLE(id INT IDENTITY(1,1), open_dt DATE, ops_hrs VARCHAR(32));

INSERT @x(open_dt, ops_hrs) VALUES
    ('2011-10-31', '7:00AM - 5:30PM'),
    ('2011-11-01', '7:00AM - 5:00PM'),
    ('2011-11-02', '7:00AM - 5:00PM'),
    ('2011-11-03', '7:00AM - 5:00PM'),
    ('2011-11-06', '7:00AM - 7:00PM'),
    ('2011-11-08', '7:00AM - 5:00PM');

;WITH d AS
(
    SELECT open_dt, ops_hrs, max_date = COALESCE((SELECT MAX(open_dt)
        FROM @x AS b WHERE b.open_dt > a.open_dt 
        AND NOT EXISTS (SELECT 1 FROM @x AS c
          WHERE c.open_dt >= a.open_dt 
          AND   c.open_dt <  b.open_dt 
          AND   c.ops_hrs <> b.ops_hrs)), open_dt)
    FROM @x AS a
)
SELECT 
    min_date = MIN(open_dt),
    max_date, 
    ops_hrs
FROM d
    GROUP BY max_date, ops_hrs
    ORDER BY min_date;
于 2011-08-17T21:49:38.253 回答