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我们有 2 个表，分别称为 tbl_1、tbl_2 和 tbl_3。它包含 Vis_ID、Cust_ID 等列。在某些情况下，一个 Vis_ID 将与多个 Cust_ID 相关联。

例如，如果客户登录一个网站，每次访问该网站都会生成一个唯一的 Vis_ID。

一次访问，多个客户可以登录他们的帐户并进行个人购买。在某些情况下，访问将与多个客户 ID 相关联。如果实例超过 2 个，请在此列中附加任何其他零售客户 ID 实例。

例如有访问，该访问附加了 100 个 Cust_ID。

例如，如果 1 次访问中有 5 个 Cust_ID，对于客户 1，它应该有第一个客户 1。对于客户 2，我们需要显示第二个 Cust_ID。

对于 3rd 到 5th Cust_IDs ，我需要以逗号分隔显示这些记录。

with CTE as (
    SELECT
    Vis_ID,
    B.pg_no::INT AS pg_no,
     CUST_ID,
  dense_rank()over( PARTITION BY Vis_ID order by CUST_ID) as rank
from
    db_name.schema_name.tbl_1 A
    JOIN db_name.schema_name.tbl_2 B
    ON B.id_column  = A.id_column 
    JOIN db_name.schema_name.tbl_3 C
    ON CAST(C.xid as VARCHAR)= A.CUST_ID
    WHERE flg_col = '0'
    AND so_cd NOT IN ('0','1','2','3')
    AND DATE_COL = '2022-01-17'
    and Vis_ID='12345'
      ORDER BY pg_no
    )
    
    select  Vis_ID, arr[0], arr[1], array_to_string( array_slice(arr, 2, 99999), ', ')
    from (
    select Vis_ID, array_agg(distinct CUST_ID) within group(order by CUST_ID) arr
    from CTE
    group by 1
    );


When I run the below query that I have included inside CTE separately, I'm getting records which are duplicates.

SELECT Vis_ID, B.pg_no::INT AS pg_no, CUST_ID, dense_rank()over( PARTITION BY Vis_ID order by CUST_ID) 作为 db_name.schema_name.tbl_1 A JOIN db_name.schema_name.tbl_2 B ON B.id_column = A.id_column 的排名JOIN db_name.schema_name.tbl_3 C ON CAST(C.xid as VARCHAR)= A.CUST_ID WHERE flg_col = '0' AND so_cd NOT IN ('0','1','2','3') AND DATE_COL = '2022-01-17' 和 Vis_ID='12345' ORDER BY pg_no

以下重复结果：

    Row      VISIT_ID    CUSTOMER_ID          VISITPG_NBR     RANK 
**1         12345      100                      1                1**
2         12345      100                      2                1
3         12345      100                      3                1
4         12345      100                      4                1
5         12345      100                      5                1

**6         67891      101                      6                2**
7         67891      101                      7                2
8         67891      101                      8                2
9         67891      101                      9                2
10        67891      101                      10               2

**11        78910      102                      11               3**
12        78910      102                      12               3
13        78910      102                      13               3
14        78910      102                      14               3

Is there any logic to display the distinct results in the CTE temp table?

最终结果应显示如下。

VIS_ID    First_Customer  Second_Customer   Other_Customers

1            100            101             102,103,104,105,106
2            200            201             202,203,204,205

我还希望结果按 pg_no 排序

请指导。

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