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我正在尝试获取特定类型的电影名称并运行我的下面的函数，然后我才得到英文电影的名称现在它应该像这样“黑暗骑士”而不是“黑暗骑士”应该给出下面的函数工作正常，在他们给我确切的英文版本名称之前！我真的很惊讶也很沮丧

Action_soup = site_soup('https://www.imdb.com/search/title/?.....')
Action_soup.find_all(class_ = 'lister-item-header')

def site_soup(link):
  r = requests.get(str(link), auth=("user",'pass'))
  soup = bs(r.content)
  return soup


#create the function for specific genres movies list
def movies_list(st,Soup):
  movies = Soup.find_all(class_ = str(st))
  movie_list = []
  for i in movies:
    movie_list.append(i.find('a').string)
  return movie_list

前一天的输出：

Action_movies[0]
:'The Dark Knight'

输出：

<h3 class="lister-item-header">
 <span class="lister-item-index unbold text-primary">1.</span>
 <a href="/title/tt0468569/">黑暗騎士</a>
 <span class="lister-item-year text-muted unbold">(2008)</span>
 </h3>, <h3 class="lister-item-header">
4

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