directoryentry - 给定用户的 SID，我如何获取 AD DirectoryEntry？

Question

我有用户的 SIDbyte[]在windowsPrincipal.getIdentity().getSid(). 如何从 SID 获取 Active Directory 条目 (DirectoryEntry)？

Answer 1

使用SecurityIdentifier类将 sid 从 byte[] 格式转换为字符串，然后直接绑定到对象：

DirectoryEntry OpenEntry(byte[] sidAsBytes)
{
    var sid = new SecurityIdentifier(sidAsBytes, 0);

    return new DirectoryEntry(string.Format("LDAP://<SID={0}>", sid.ToString()));
}

Answer 2

我在 c# 中找到了这个例子

    // SID must be in Security Descriptor Description Language (SDDL) format
    // The PrincipalSearcher can help you here too (result.Sid.ToString())
    public void FindByIdentitySid()
    {
        UserPrincipal user = UserPrincipal.FindByIdentity(
            adPrincipalContext,
            IdentityType.Sid,
            "S-1-5-21-2422933499-3002364838-2613214872-12917");
        Console.WriteLine(user.DistinguishedName);
    }

转换为 VB.NET：

    ' SID must be in Security Descriptor Description Language (SDDL) format
    ' The PrincipalSearcher can help you here too (result.Sid.ToString())
    Public Sub FindByIdentitySid()
        Dim user As UserPrincipal = UserPrincipal.FindByIdentity(adPrincipalContext,     IdentityType.Sid, "S-1-5-21-2422933499-3002364838-2613214872-12917")
        Console.WriteLine(user.DistinguishedName)
    End Sub

显然你可以：

    dim de as new DirectoryEntry("LDAP://" & user.DistinguishedName)

获取 SID = S-1-5-21- *（对不起 VB.NET）

    ' Convert ObjectSID to a String

    ' http://social.msdn.microsoft.com/forums/en-US/netfxbcl/thread/57452aab-4b68-4444-aefa-136b387dd06e

    Dim ADpropSid As Byte()
    ADpropSid = de.Properties("objectSid").Item(0)    
    ' in my test the byte field looks like this : 01 02 00 00 00 00.......37 02 00 00
    Dim SID As New System.Security.Principal.SecurityIdentifier(ADpropSid, 0)

我自己还没有测试过 C# 或使用过转换后的版本，但是已经使用上面的方法以 SDDL 格式返回 SID。

Answer 3

我发现最简单的方法是使用 LDAP 绑定。类似于尼克吉尔斯所说的。更多信息在MSDN

''' <summary>
''' Gets the DirectoryEntry identified by this SecurityIdentifier.
''' </summary>
''' <param name="id">The SecurityIdentifier (SID).</param>
<System.Runtime.CompilerServices.Extension()> _
Public Function GetDirectoryEntry(ByVal id As SecurityIdentifier) As DirectoryEntry
    Const sidBindingFormat As String = "LDAP://AOT/<SID={0}>"

    Return New DirectoryEntry(String.Format(sidBindingFormat, id.Value))
End Function

Answer 4

这也可以在 PowerShell 中完成，只要您有 .Net 3.5 或 4.0 可用（如果默认情况下没有，请参阅https://gist.github.com/882528 ）

add-type -assemblyname system.directoryservices.accountmanagement
$adPrincipalContext = 
    New-Object System.DirectoryServices.AccountManagement.PrincipalContext( 
    [System.DirectoryServices.AccountManagement.ContextType]::Domain)
$user = [system.directoryservices.accountmanagement.userprincipal]::findbyidentity(
    $adPrincipalContext
    , [System.DirectoryServices.AccountManagement.IdentityType]::Sid
    , "S-1-5-21-2422933499-3002364838-2613214872-12917")
$user.DisplayName
$user.DistinguishedName