我正在使用 3rd 方 wsdl 创建一个 Web 服务,它可以帮助我获得某种通知。现在我必须将该通知保存在数据库中并执行与数据库相关的其他几个操作。在我的 persistence.xml 中有两个持久性单元如下:
<persistence-unit name="PU1" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/vsDS</jta-data-source>
<class>com.Response</class>
<class>com.Request</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="eclipselink.logging.level" value="INFO"/>
</properties>
</persistence-unit>
<persistence-unit name="PU2" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/vdDS</jta-data-source>
<class>com.LogRequest</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="eclipselink.logging.level" value="INFO"/>
</properties>
</persistence-unit>
到目前为止,我已经创建了一个名为 Service.java 的类,它具有我需要在 DB 上执行的所有功能,如下所示:
public class Service {
private static Logger logger = Logger.getLogger(Service.class);
private EntityManagerFactory PU1;
private EntityManagerFactory PU2;
public Service(){
System.out.println("in service's constructer");
PU1=Persistence.createEntityManagerFactory("PU1");
PU2=Persistence.createEntityManagerFactory("PU2");
}
public void logSubRequest(String msg){
EntityManager em= PU1.createEntityManager();
try{
em.getTransaction().begin();
Request req=new Request();
req.setMessage(msg);
req.setStatus("Y");
em.persist(req);
em.getTransaction().commit();
}catch(Exception e){
logger.error("In logSubRequest="+e.getMessage());
e.printStackTrace();
}finally{
if(em.isOpen()){
em.close();
}
}
}
// there are several other methods of such kind that either persist entities or executeUpdate
}
我的问题是:我是采用标准方法来实现带有 web 服务的 JPA,还是应该采用其他一些技术/方法。如果我做任何不合标准的事情,请建议和指导。