3

我正在尝试编写一些代码,用于显示 Laravel 数据库中的数据。但是我有两个用外键相互链接的表值,当我尝试在我的页面上显示它时,它只显示 id 而不是实际名称。我在另一个 stackoverflow 问题中看到您应该在您的模型中定义表数据值,但这不起作用或者我做错了。有人可以帮我解决这个问题吗?:)

模型Planet.php:

<?php

namespace App\Models;

use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;

class Planet extends Model
{
    public function solar()
    {
    return $this->belongsTo(SolarSystems::class, 'id');
    }
}

SolarSystems.php 模型:

<?php

namespace App\Models;

use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;

class SolarSystems extends Model
{
    public function planet()
    {
        return $this->belongsTo(Planet::class, 'solar_systems_id');
    }
}

行星控制器.php:

<?php

namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Models\Planet;
use App\Models\SolarSystems;

class PlanetController extends Controller
{
    public function index()
    {
        $planets = Planet::all();
        $solar = SolarSystems::all();

        return view('welcome', ['planets'=>$planets]);
    }
    public function show($planeet)
    {
        $planets = Planet::all();
        $solar = SolarSystems::all();
    
        $planets = collect($planets)->where('name', $planeet);
        return view('welcome', ['planets' => $planets]);
    }
}

欢迎.blade.php:

<!DOCTYPE html>
<html>
    <head>
        <meta charset="utf-8">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <title>Laravel</title>
        <link href="https://fonts.googleapis.com/css2?family=Nunito:wght@400;600;700&display=swap" rel="stylesheet">
        <style>
            body {
                font-family: 'Nunito', sans-serif;
            }
        </style>
    </head>
    <body>

@foreach ($planets as $planeten)
    <ul>
        <li>{{ ucfirst($planeten->name) }}</li>
        <p>{{ ucfirst($planeten->description) }}</p>
        <p>{{ ucfirst($planeten->solar_systems_id) }}
    </ul>
@endforeach
    </body>
</html>

导入.sql:

CREATE DATABASE laravel;
USE laravel;
CREATE TABLE planets (
    id int(11) AUTO_INCREMENT,
    name text,
    description text,
    size_in_km int(11),
    solar_systems_id int(11),
    PRIMARY KEY (id)
);

CREATE TABLE solar_systems (
    id int(11) AUTO_INCREMENT,
    name text,
    age_in_years int(11),
    PRIMARY KEY (id)
);

INSERT INTO planets (name, description, size_in_km, solar_systems_id)
VALUES ('mars', 'Mars is the fourth planet from the Sun and the second-smallest planet in the Solar System, being larger than only Mercury.', 3389, 1);

INSERT INTO planets (name, description, size_in_km, solar_systems_id)
VALUES ('venus', 'Venus is the second planet from the Sun. It is named after the Roman goddess of love and beauty.', 6051, 1);

INSERT INTO planets (name, description, size_in_km, solar_systems_id)
VALUES ('earth', 'Our home planet is the third planet from the Sun, and the only place we know of so far thats inhabited by living things.', 6371, 1);

INSERT INTO solar_systems (name, age_in_years)
VALUES ('The Milky Way', 1360000000);

这就是我现在得到的,但不是“1”而是需要说:“银河系” 在此处输入图像描述

4

3 回答 3

1

您的代码几乎没有问题;

关系

你有 1-N 的关系,一个行星属于一个太阳系,一个太阳系有许多行星。

行星.php

public function solar()
{
    return $this->belongsTo(SolarSystems::class, 'solar_systems_id');
}

SolarSystems.php

public function planets()
{
    return $this->hasMany(Planet::class, 'solar_systems_id');
}

控制器

行星控制器.php

public function show($planeet)
{
    $planets = Planet
              ::with('solar')
              ->where('name', $planeet)
              ->get();
       
    return view('welcome', ['planets' => $planets]);
}

你可以看到,我正在使用withwhere优化查询。

看法

既然你已经用急切加载加载了关系,你可以直接从行星上访问模型。

 <p>{{ ucfirst($planeten->solar->name) }}
于 2022-01-26T13:09:28.030 回答
0

替换这一行

<p>{{ ucfirst($planeten->solar_systems_id) }} 

用这条线

<p>{{ ucfirst($planeten->solar()->name) }}</p> 
于 2022-01-26T12:43:13.773 回答
0

只需替换此行

{{ ucfirst($planeten->solar_systems_id) }} 

with this line 

{{ ucfirst($planeten->solar->name) }}

因为你需要从关系中得到名字

于 2022-01-26T12:50:14.913 回答