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我正在使用 assertj 和 Jackson 的 JsonNode 组合。到目前为止,我一直在使用Assertions.assertThat(objectNode0).isEqualTo(objectNode1);,一切正常。

现在,我需要忽略比较中的一些字段,我尝试的方法是使用usingRecursiveComparison,但是当对象不同时它无法提醒。有什么办法可以克服这个吗?这是我的示例代码:

public class Main {

public static void main(String[] args) {
    ObjectMapper om = new ObjectMapper();

    try {
        JsonNode objectNode0 = om.readTree("{\"someNotImportantValue\":1,\"importantValue\":\"10\"}");
        JsonNode objectNode1 = om.readTree("{\"someNotImportantValue\":15,\"importantValue\":\"1\"}");

        boolean equals = objectNode0.equals(objectNode1);
        System.out.println(equals); // prints false

        //This works, but does not enable to ignore any field
        //Assertions.assertThat(objectNode0).isEqualTo(objectNode1);

        //We would expect this sentence to fail, since importantValue is still different, but it does not.
        Assertions.assertThat(objectNode0).usingRecursiveComparison().ignoringFields("someNotImportantValue").isEqualTo(objectNode1);

    } catch (JsonProcessingException e) {
        e.printStackTrace();
    }
}

}

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1 回答 1

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JsonUnit通常是 JSON 相关断言的更好候选者,并且还与 AssertJ 集成

对于原始示例,以下断言:

assertThatJson(objectNode0).isEqualTo(objectNode1);

会失败:

net.javacrumbs.jsonunit.core.internal.Opentest4jExceptionFactory$JsonAssertError: JSON documents are different:
Different value found in node "importantValue", expected: <"1"> but was: <"10">.
Different value found in node "someNotImportantValue", expected: <15> but was: <1>.

但是,我也希望带有递归比较的 AssertJ 失败,因此我提出了https://github.com/assertj/assertj-core/issues/2459

于 2022-01-06T13:16:20.933 回答