我有一个凸底栏，最后一个选项卡是一个菜单，单击时会打开一个抽屉。但是当抽屉关闭时我遇到了麻烦。由于选项卡菜单仅打开一个抽屉，我希望它可以在抽屉关闭时返回到上一个选项卡，但菜单选项卡保持活动状态。该选项卡仅在单击时更改。那么如何在抽屉关闭时调用convex_tab_bar的onTab属性呢？
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return Scaffold(
key: _scaffoldKey,
drawer: Drawer(
child: ListView(
padding: EdgeInsets.zero,
children: [
const DrawerHeader(
decoration: BoxDecoration(
color: Colors.blue,
),
child: Text('Drawer Header'),
),
ListTile(
title: const Text('Item 1'),
onTap: () {},
),
],
),
),
onDrawerChanged: (isOpen) {
if (!isOpen) {
setState(() {
_currentOption = _previousOption;
});
changeTab(context, _previousOption);
}
},
body: Container(
child: _currentPage,
),
bottomNavigationBar: StyleProvider(
style: Style(),
child: ConvexAppBar(
style: TabStyle.fixedCircle,
backgroundColor: Colors.white,
color: Colors.grey,
activeColor: _currentOption == 1
? const Color(0xffa98e47)
: const Color(0xff00c9ff),
items: [
TabItem(
icon: const Icon(
ReceivedIcon.receivedIcon,
color: Colors.grey,
size: 12,
),
title: AppLocalizations.of(context)!.received,
activeIcon: const Icon(
ReceivedIcon.receivedIcon,
color: Color(0xff00c9ff),
size: 12,
),
),
TabItem(
icon: const Icon(SentIcon.sentIcon, color: Colors.grey),
title: AppLocalizations.of(context)!.sent,
activeIcon: const Icon(SentIcon.sentIcon, color: Color(0xffa98e47)),
),
const TabItem(
icon: Icon(
Icons.add_rounded,
size: 48,
color: Colors.white,
)
),
TabItem(
icon: Icons.notifications,
title: AppLocalizations.of(context)!.notifications
),
TabItem(
icon: Icons.menu,
title: AppLocalizations.of(context)!.menu
),
],
onTap: (int i) {
changeTab(context, i);
},
),
),
);