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class Employee
 include Mongoid::Document
 include Mongoid::Timestamps
 
 STATUSES = ["pending", "approved", "pending_approval", "rejected"]
 field :status, type: String, default: "pending"
 
 belongs_to :department
end


class Department
 include Mongoid::Document
 include Mongoid::Timestamps
 
 DEPARTMENTS = ["it", "account", "business", "marketing"]
 field :name, type: String
 
 has_many :employees
end

有 Employee 和 Department 两种模型

我需要获取员工的部门和状态计数以及状态计数总数。

[
 # department wise count
 {department_id: 1, pending_count: 5, approved_count: 3, pending_approval_count: 3, rejected: 1},
 {department_id: 2, pending_count: 2, approved_count: 1, pending_approval_count: 5, rejected: 1},
 {department_id: 3, pending_count: 4, approved_count: 2, pending_approval_count: 1, rejected: 2},
 {department_id: 4, pending_count: 1, approved_count: 3, pending_approval_count: 1, rejected: 1},
 #Total count of above counts
 {total_pending_count: 12, total_approved_count: 9, total_pending_approval_count: 10, total_rejected: 5},
]

就像我需要的这种类型的数据。

知道这里需要使用什么聚合查询吗？

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0 回答 0